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V125BC [204]
3 years ago
10

What is 84,052 in word form

Mathematics
2 answers:
Sedbober [7]3 years ago
6 0
eighty four thousand fifty two
Radda [10]3 years ago
6 0

\text {Hello! Let's Solve this Problem!}

\text {To write numbers in word form you have to look at the place it's in}

\text {8 = 80,000 = Eighty Thousand}\\\text {4 = 4,000 = Four Thousand}\\\text {0 = 0 = Zero}\\\text {5 = 50 = Fifty}\\\text {2 = 2 = Two}

\text {Your Answer Would Be:}

\huge\boxed {\text {Eighty Four Thousand Fifty Two}}

\text {Best of Luck!}

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Is y greater than negative infinity or less than in this graph?
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The arrows indicates the line will go on forever. This is called a ray, a line that will go on infinitely.

The line is neither greater than or equal to.

The line is infinite.

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Find the volume: 8 ft 4 ft 14.5 ft<br>help pls-?​
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Hydrogen bonds occur only when hydrogen is covalently bonded to one of three elements: fluorine, oxygen, or nitrogen. Anything else isn't considered a hydrogen bond.

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3 years ago
How do i check if 12=x-4 is 16
My name is Ann [436]

Answer:

x=16

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3 years ago
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You are standing 30 meters from a hot air balloon that is preparing to take
Lerok [7]

Answer:

The distance to the top of the balloon is approximately 33.977 meters

Step-by-step explanation:

The (horizontal) distance from the hot air balloon from the observer, <em>l</em> = 30 m

The angle of elevation to the top of the balloon, θ = 28°

With the balloon standing upright, the distance to the top of the balloon, <em>d</em>, the height of the balloon, <em>h</em> and the horizontal distance to the balloon, <em>l</em>, form a right triangle, where;

d = The hypotenuse side

l = The leg adjacent to the reference (given) angle,

h = The leg opposite to the given angle, θ

By trigonometric ratios, we have;

cos\angle X = \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length}

From which we get;

cos\angle \theta = \dfrac{l}{d}

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d = \dfrac{30 \ m}{cos(28^{\circ}) } \approx 33.977 \, m

The distance to the top of the balloon, <em>d </em>≈ 33.977 m

8 0
3 years ago
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