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V125BC [204]
3 years ago
10

What is 84,052 in word form

Mathematics
2 answers:
Sedbober [7]3 years ago
6 0
eighty four thousand fifty two
Radda [10]3 years ago
6 0

\text {Hello! Let's Solve this Problem!}

\text {To write numbers in word form you have to look at the place it's in}

\text {8 = 80,000 = Eighty Thousand}\\\text {4 = 4,000 = Four Thousand}\\\text {0 = 0 = Zero}\\\text {5 = 50 = Fifty}\\\text {2 = 2 = Two}

\text {Your Answer Would Be:}

\huge\boxed {\text {Eighty Four Thousand Fifty Two}}

\text {Best of Luck!}

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Aleksandr-060686 [28]
There would be an open circle on positive 12 with the arrow moving to the right.
7 0
3 years ago
What is x for -3(x+5)=-9
Andrew [12]
-3(x+5)=-9
-3x-15=-9
+15 +15
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3 0
3 years ago
Read 2 more answers
2. The cost of a bicycle is * 2895. Find the cost of 1486 bicycles,
forsale [732]

Answer:

4,301,970

5,149,815

Step-by-step explanation:

The cost of a bicycle is 2895

Therefore the cost of 1486 bicycles is

= 2895×1486

= 4,301,970

A truck can carry 6785 kg of food

Therefore the amount in which 759 truckj can carry can be calculated as follows

= 6785×759

= 5,149,815

7 0
3 years ago
Mathematically derive a set of values for b and c such that the interval [0, 10] represents the solution to the inequality |x−b|
Roman55 [17]

Answer: Ix - 5I ≥ 5.

Step-by-step explanation:

We want the set:

[0, 10]

to be the solution of:

Ix - bI ≤ c

So we need to find the values of c and b.

The first step is to find the middle point in our segment.

We can do that by adding the extremes and dividing it by 2.

M = (10 + 0)/2 = 5

And we also want to find half of the difference between the extremes, this is:

D = (10 - 0)/2 = 5.

Now, this set will be the set of solutions of:

Ix - MI ≥ D

Then in our case, we have:

Ix - 5I ≥ 5.

so we have that b = 5, and c = 5.

8 0
3 years ago
Cost of 10 oranges is one dollar what is the cost of five
aleksley [76]
10 oranges = $1
5 oranges = $?

To get from 10 to 5 you divide by 2 so that’s what you do with the $1 so it would be $0.50
8 0
3 years ago
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