The perimeter of a rectangle garden is 364 feet. If the width of the garden is 85 feet, what is it length?

Mathematics

1 answer:

kherson [118]2 years ago

6 0

P=2(L+W)

P=364

L=99

sub and find W

364=2(99+W)

divide both sides by 2

182=99+w

subtract 99 from both sides

83=W

w=83ft

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100 points for the answer

lora16 [44]

Answer:

83 in.^2

Step-by-step explanation:

The entire polygon consists of a rectangle with length 8 in. and width 5 in., a triangle with base 8 in. and height 7 in., and another triangle with base 5 in. and height 6 in.

The total are is the sum of the area of the rectangle and the two triangles.

area = area of rectangle + area of first triangle + area of second triangle

area = LW + bh/2 (for the first triangle) + bh/2 (for the second triangle)

area = 8 in. * 5 in. + 8 in. * 7 in. / 2 + 5 in. * 6 in. / 2

area = 40 in.^2 + 28 in.^2 + 15 in.^2

area = 83 in.^2

7 0

3 years ago

Read 2 more answers

number 3 says,"If u and v are the measures of complementary angles such that sin u =2/5 and tan v =(square root of 21) 21/2, lab

vodomira [7]

Answer and Explanation:

Using trig ratios, we can express the given values of sin u and tan v as shown below

$\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}$

So we can go ahead and label the sides of the triangle as shown below;

We can find the value of u as shown below;