Answer:
Answer Choice D
Step-by-step explanation:
Does not pass the vertical line test but the rest of the answer choices do which makes D not a function and your solution.
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Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.
In this case, we could say (where
is the area of the rectangle):

Substituting the values the problem gave us for
and
, we can find the formula for
in terms of
, which is:

The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.
Answer:

Step-by-step explanation:
<u>Given: </u>
line y=3x-1
point (-3,0)
<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)
<u>Solution:</u>
The slope of the given line is 
If
is the slope of perpendicular line, then

So, the equation of the needed line is 
Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (4, 7)
m =
=
= 2
Answer: see below
<u>Step-by-step explanation:</u>
The coordinates on the Unit Circle are (cos, sin). Since we are focused on cosine, we only need to focus on the left side of the coordinate. The cosine value (left side) will be the y-value of the function y = cos x
Use the quadrangles (angles on the axes) to represent the x-values of the function y = cos x.
Quadrangles are: 0°, 90°, 180°, 270°, 360° <em>(360° = 0°)</em>
Together, the coordinates will be as follow:
