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jeka57 [31]
3 years ago
12

Solve each equation 4x=38-2(x+4)

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

To solve this equation, we will have to solve for x.

4x = 38 - 2(x + 4)

Distribute the 2 on the right side of the equation.

4x = 30 - 2x - 8

Combine like terms.

4x = 30 - 2x

Add 2x to both sides of the equation.

6x = 30

Divide both sides by 6.

x = 5

So the solution to the equation would be x = 5.

I hope you find my answer and explanation helpful. Happy studying. :)

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lakkis [162]

Answer:

\frac{x}{3}  + 4 =  \frac{4x - 1}{5}  \\  \\  \frac{x}{3}  +  \frac{12}{3}  =  \frac{4x - 1}{5}  \\  \\  \frac{x + 12}{3}  =  \frac{4x - 1}{5}  \\  \\ 3(4x - 1) = 5(x + 12) \\  \\ 12x - 3 = 5x + 60 \\  \\ 12x - 5x = 60 + 3 \\  \\ 7x = 63 \\  \\ x =  \frac{63}{7}  \\  \\ x = 9

7 0
3 years ago
Which fraction is equal to 0.8? Express your answer in simplest form. A. 3/5 B. 4/5 C. 1/8 D. 5/8
Murrr4er [49]
0.8 = 0.8 \times \frac{10}{10} = \frac{8}{10} =\frac{4\times 2}{5\times 2} = \boxed{\bf{\frac{4}{5}}}

Answer is B
4 0
3 years ago
Using d= rt, find r if d= 350 miles and t= 5 hours
lubasha [3.4K]

Answer:

70 miles /hour = r

Step-by-step explanation:

d=rt

Substitute d=350 miles and t = 5 hours

350 miles = r* 5 hours

Divide each side by 5 hours

350 miles = 5 hours = r

70 miles /hour = r

3 0
3 years ago
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( , ). The coordinates of the point that is
AURORKA [14]

Answer:

Reflection across the x-axis: (-4,2)

Reflection across the y-axis: (4,-2)

Step-by-step explanation:

Going based off of what I see, a reflection across the x axis changes "y" & the same rule applies to the y axis.

It should be an L shape.

7 0
4 years ago
a company bought 12 boxed lunches from a delli for $74.50 each boxed lunch costs the same amount which equation represents the p
Snowcat [4.5K]
I they each cost 6.21$ caz if u do 6.21 you get 74.53 but if you do 6.20 you get74.40 what ever u prefer
4 0
4 years ago
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