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2 years ago

10

Six times a number is greater than 20 more than that number. What are the possible values of that number? n less-than 4 n greate

r-than 4 n greater-than StartFraction 20 Over 7 EndFraction n less-than StartFraction 20 Over 7 EndFraction

2 answers:

MrRissso [65]2 years ago

7 0

Answer: answer is b

Step-by-step explanation: because ik

mel-nik [20]2 years ago

4 0

Answer:

b

Step-by-step explanation:

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denis-greek [22]

Answer:

B

Step-by-step explanation:

4 0

2 years ago

Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84

guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0

1 year ago

How to find equation hyperbola with asymptotes, center and transverse?

lapo4ka [179]

The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.

6 0

2 years ago

An arc with length 5 pi over 4 inches is formed by a 15 degree central angle what is the radius of the circle

Natalka [10]

Answer:

Radius of the circle is <em>15 inches.</em>

<em></em>

Step-by-step explanation:

Relation between length of arc, radius and the angle subtended by the arc on center is:

$\theta = \dfrac{l}{r} ..... (1)$

where $\theta$ is the central angle in radians subtended by arc

$l$ is the length of arc

$r$ is the radius of arc

We are Given the following details:

$l = \dfrac{5\pi}{4}\ inch$

$\theta = 15^\circ$

We know that $\pi \ radians = 180 ^\circ$

Converting $\theta$ to radians:

$\theta =\dfrac{\pi}{180} \times 15$ radians

Putting the values of $\theta$ and $l$ to find the value of $r$

$\dfrac{\pi}{180} \times 15 = \dfrac{5\pi}{4r}\\\Rightarrow r = \dfrac{45}{3} \\\Rightarrow r = 15 \ inches$

Hence, Radius of the circle is <em>15 inches.</em>

6 0

2 years ago

Mark is covering an 8-inch-square board with 1-inch-square tiles. He uses gray tiles to make four 2-in. by 2-in. squares. He cov

KonstantinChe [14]

48 because if you take the total area and subtract the area of the small squares you get 48 square inches left white

6 0

2 years ago