Answer: ≈ 185.73009
Step-by-step explanation:
area of square: 
area of circle: 
length: 15
radius = diameter/2
radius: 5
area of square - area of circle = area between square and circle:
≈ 185.73009
hope it helps!
Please mark as brainliest.
The answer is -16 and -5.
Answer:
Serina should have solved for x in the second equation because it has a coefficient of 1.
Step-by-step explanation:
we have
----> equation A
---> equation B
we know that
To solve the system of equations in the most efficient way, solve for x equation B and then substitute the value of x in equation A
so
----> equation C
substitute equation C in equation A

solve for y

Find the value of x
substitute the value of y in the equation C

The solution is (3,4)
therefore
Serina should have solved for x in the second equation because it has a coefficient of 1.
(17-5=12-1=11+8=19-2=(17-3=14)-3=11-3=8-3=5) wait maybe I got this mixed up with somthing else but...
<span>We know that OB bisects EC where they intersect would be at point O,
so the two lengths EO and OC must be equal.
2x - 20 = 70 - x
</span>[adding x + 20 to each side]
2x - 20 + x + 20 = 70 - x + x + 20
[simplifying]
<span>3x = 90
</span>[dividing each side by 3]
<span>
x = 30 would be the answer</span>