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Nesterboy [21]
3 years ago
15

Plz answer it need it very fast!!! Will give brainiest

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0
60
Because If you go by there score on paper 5 and follow it up to the line of best fit and then go across to the paper 2 in lines up to 60
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Which impact did new consumer goods have on the lives of Texans in the 1920's?
nadezda [96]

Answer:

Consumption in the 1920s The prosperity of the 1920s led to new patterns of consumption, or purchasing consumer goods like radios, cars, vacuums, beauty products or clothing. The expansion of credit in the 1920s allowed for the sale of more consumer goods and put automobiles within reach of average Americans.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A normally distributed population has mean 57,800 and standard deviation 750. Find the probability that a single randomly select
Stels [109]

Answer:

(a) Probability that a single randomly selected element X of the population is between 57,000 and 58,000 = 0.46411

(b) Probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = 0.99621

Step-by-step explanation:

We are given that a normally distributed population has mean 57,800 and standard deviation 75, i.e.; \mu = 57,800  and  \sigma = 750.

Let X = randomly selected element of the population

The z probability is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

(a) So, P(57,000 <= X <= 58,000) = P(X <= 58,000) - P(X < 57,000)

P(X <= 58,000) = P( \frac{X-\mu}{\sigma} <= \frac{58000-57800}{750} ) = P(Z <= 0.27) = 0.60642

P(X < 57000) = P( \frac{X-\mu}{\sigma} < \frac{57000-57800}{750} ) = P(Z < -1.07) = 1 - P(Z <= 1.07)

                                                          = 1 - 0.85769 = 0.14231

Therefore, P(31 < X < 40) = 0.60642 - 0.14231 = 0.46411 .

(b) Now, we are given sample of size, n = 100

So, Mean of X, X bar = 57,800 same as before

But standard deviation of X, s = \frac{\sigma}{\sqrt{n} } = \frac{750}{\sqrt{100} } = 75

The z probability is given by;

           Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  

Now, probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = P(57,000 < X bar < 58,000)

P(57,000 <= X bar <= 58,000) = P(X bar <= 58,000) - P(X bar < 57,000)

P(X bar <= 58,000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{58000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z <= 2.67) = 0.99621

P(X < 57000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{57000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z < -10.67) = P(Z > 10.67)

This probability is that much small that it is very close to 0

Therefore, P(57,000 < X bar < 58,000) = 0.99621 - 0 = 0.99621 .

7 0
3 years ago
Will give brainliest.
Olenka [21]

You need to give us the equation first, otherwise we can't do it

:|

8 0
3 years ago
What are the coordinates of the endpoints A'B after a reflection of segment AB over the line y = - x?
kupik [55]

Answer:

by reflection, if you mean swapped, then the answers are A'(1,-6) and B'(4,2)

i hope these are the answers you are looking for

Step-by-step explanation:

6 0
2 years ago
What is the greatest common factor of 10, 20, and 50?
Viefleur [7K]

Answer:

10

Step-by-step explanation:

first you need to find the prime factors of the three numbers

ex:

prime factor of 18= 2*3*3

prime of 24=2*2*2*3

there is one 2 and one 3 in common

greatest common multiple 2*3=6

so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

10=10/10=1\\20=20/10=2\\50=50/10=5

so 10 is your answer

6 0
3 years ago
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