Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
<span>DE = EB
DE = p + 15
I would help you farther but I don't know what p equals. If you know then add that number with 15 and you have your answer.</span><span />
[ (3 · 7) - 6 ] · 5 = [ 21 - 6 ] · 5 = 15 · 5 = 75
Answer: 
<u>Find Common Denominator</u>
2: 2,4,6,8,10
4: 4,8,12,16,20
CD=4
<u>Add</u>
1/4+2/4=3/4
3/4=.75
Answer:
none
Step-by-step explanation:
No choice is correct.
The original expression has 560 x 70, the product of 560 and 70 inside the parentheses.
(560 x 70) ÷ 10 is 10 times smaller than 560 x 70
None of the choices show 560 x 70. They show 560 + 70 and 560 - 70.
Answer: none
