since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

3 years ago

Consuela earns a salary of 40000$ per year plus commission of 1000$ for each car she sells. Write and solve an equation that sho

iVinArrow [24]

40000+1000x=60000
-40000. -40000

1000x=20000
x=20

6 0

3 years ago

I need to find the area of this

Olegator [25]

The answer is 130 inches squared

7 0

3 years ago

Can you PLEASE PLEASE help me with this question!!!!

svlad2 [7]

4% of 200 7 graders= 8, so 8 are expected to move by the end of the year. but if 12 students actually moved instead, there was 4 more moves than we expected. I hope this helped..!

4 0

3 years ago