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JulsSmile [24]
2 years ago
14

Use the GCF and the Distributive property to find the sum of 66+78

Mathematics
1 answer:
taurus [48]2 years ago
4 0

Here is ur answer of your question

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The positions of two villages A and B. Village B is 100km away and on a bearing of 083° from village A.
blagie [28]

Answer:

23•1

Step-by-step explanation:

83°/360°×100km=23•1

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The answer is x = 6

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Liono4ka [1.6K]

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Step-by-step explanation:

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In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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3 years ago
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Median for 35 45 26 32 46 38 39 40 26 72
zhenek [66]

Answer:

38.5

Step-by-step explanation:

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