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ddd [48]
3 years ago
6

En una casa de empanadas hornean 1.200 por día. Si las cocinan en fuentes de 75 unidades, colocando siempre la mayor cantidad po

sible, ¿Cuántas fuentes preparan?
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

16 unidades preparan simultáneamente 1200 empanadas por día.

Step-by-step explanation:

Si cada fuente tiene una capacidad de 75 empanadas por horneada y que la mayor cantidad posible ocurre cuando el volumen de producción se cocina simultáneamente, entonces el total de fuentes es la cantidad total de producción dividida por la capacidad de empanadas por fuente. Es decir:

x = \frac{1200\,emp}{75\,\frac{emp}{und} }

x = 16\,unidades

16 unidades preparan simultáneamente 1200 empanadas por día.

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