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marysya [2.9K]
3 years ago
9

Ms. Carson’s art class made a large rectangular mural. The length of the mural is 9 feet, and its area is 72 square feet. What i

s the width of the mural? What is the perimeter of the mural?
Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0
Width is 8ft, Perimeter is 34ft
Mazyrski [523]3 years ago
7 0
The width of the mural is 8ft... how'd I get that??? First , you need to know the formula for the area of a rectangle ... A = LxW. The length is 9 , so what number multiplied by 9 equals 72? 8! 9x8=72 . The perimeter equals 35 feet . How'd I get that??? The width and length should both be multiplied by 2 . 9x2=18 and 8x2=16 . 18+16=35 feet !
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3 years ago
This is the result of solving an equation to find a value(s) for the variable(s)
777dan777 [17]

How the equation becomes true is given below.

Step-by-step explanation:

In an equation with one variable, the variable has a solution, or value, that makes the equation true.

  • An equation is a mathematical statement that asserts the equivalence of two expressions.
  • When an equation contains a variable, such as  x , the variable is considered an unknown value.
  • The values of the variables that make the equation true are the solutions of the equation and can be found by solving the equation.
  • A solution of an equation can be verified, or checked, by substituting in its value for the variable in the equation.

For example, the assertion that “two plus five equals seven” is represented by the equation  2 + 5 =7 .

In many cases, an equation contains one or more variables. These are still written by placing each expression on either side of an equals sign ( = ). For example, the equation  x + 3 = 5 , read “ x  plus three equals five”, asserts that the expression  x + 3  is equal to the value 5.

When an equation contains a variable such as  x , this variable is considered an unknown value. In many cases, we can find the possible values for  x  that would make the equation true.  For example, consider the equation we were talking about above:  x + 3 = 5 . You have probably already guessed that the only possible value of  x  is 2, because you know that  2 + 3 = 5  is a true equation. We use an equals sign to show that we know the value of a given variable. In this case, we write  x = 2  (read as “ x  equals two”).

The values of the variables that make an equation true are called the solutions of the equation. In turn, solving an equation means determining what values for the variables make the equation a true statement.

The equation above was fairly straightforward; it was easy for us to identify the solution as  x = 2

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8 0
3 years ago
1. Find 1/8 x 2/3 *
mash [69]

1. is 1/12. 2. is 1 3/7

8 0
3 years ago
Please answer correctly, I’ll give brainlest.
nikdorinn [45]
Your picture isn’t coming up
7 0
4 years ago
Read 2 more answers
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
4 years ago
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