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3 years ago

Graph f(x)=1.99x+3 HURRY 27 BRAINLY POINTS

Mathematics

2 answers:

dlinn [17]3 years ago

6 0

Answer:

0, 3

Step-by-step explanation:

Vlad1618 [11]3 years ago

5 0

The answer is 0 , 3 Hope this helps you

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Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.

Verdich [7]

The potential roots of the function are, $\pm1, \ \pm3, \ \pm5, \ \pm9,\ \pm15, \ \pm45,\ \pm \dfrac{1}{3},\ \pm \dfrac{5}{3}$

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; $\rm f(x) = 3x^3 - 13x^2 -3x + 45$

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

$\rm f(x) = 3x^3 - 13x^2 -3x + 45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

$\rm p=\dfrac{All\ the \ positive}{Negative\ factors \ of\ 45}$

$\rm q=\dfrac{All\ the \ positive}{Negative\ factors \ of\ 3}$

The factor of the term 45 are,

$\pm1, \ \pm3, \ \pm5, \ \pm9,\ \pm15, \ \pm45$

And The factor of 3 are,

$\pm1, \ \pm3$

All the possible roots are,

$\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\ \pm15, \ \pm45,\ \pm \dfrac{1}{3},\ \pm \dfrac{5}{3}$

Now check for all the rational roots which are possible for the given function,

$\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0$

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, $\pm1, \ \pm3, \ \pm5, \ \pm9,\ \pm15, \ \pm45,\ \pm \dfrac{1}{3},\ \pm \dfrac{5}{3}$ .

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

8 0

2 years ago

Mary drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Mary drove h

ELEN [110]

There are two separate equations for this question that use the same variable.

Mary took 7 hours to complete a trip with traffic. This would use the following expression:

$7x$

Mary took 4 hours to complete the same trip without traffic. The average rate of speed was 27 mph faster than the trip with traffic. This uses the following expression:

$4(x+27)$

Both trips had the same distance. From the information provided, we can set up the following equation:

$7x = 4(x+27)$

x represents the average rate of speed on both trips.

Distribute 4 to each term in parentheses:

$4 \times x = 4x$
$4 \times 27 = 108$

$7x = 4x + 108$

Subtract 4x from both sides:

$3x = 108$

Divide both sides by 3 to get x by itself:

$x = 36$

The average speed for the slower trip is 36 mph.

We can plug this value into the first equation:

$7(36) = 7 \times 36 = 252$

Mary lives 252 miles away from the mountains.

7 0

3 years ago

PLS HELP

Sloan [31]

Answer:

8√5 units.

Step-by-step explanation:

See the diagram in the coordinate plane attached.

A rhombus has four equal sides and to find the perimeter of the rhombus we have to measure any of the sides of the figure of the rhombus.

The coordinates of the topmost point are (-1,-1) and that of the rightmost point are (3,-3).

Therefore, side length of the rhombus will be

$\sqrt{(- 1 - 3)^{2} + (- 1 - (- 3))^{2}} = \sqrt{20} = 2\sqrt{5}$ units.