Answer:
1) The reflection of a preimage (x, y) across the line y = x gives the image (y, x)
Therefore, the the coordinates of the points L, M, and N interchange to give an image of the triangle that is apparently rotated 90° clockwise, on the opposite quadrant and equidistant from the line y = x
2) Where the line segment drawn from point L to the reflecting line is horizontal, and the line segment drawn from point L to the reflecting line is horizontal, the two line segment will be of the same length and separated vertically separated vertically by a distance equal to the sum of the absolute values of the x and y coordinates of the point L
When the line segment from point L is drawn perpendicular to the reflecting line, the line segment from point L' drawn perpendicular to the reflecting line will meet the the perpendicular line segment at the same point of intersection of the line from the point L and the reflecting line
3) Yes
4) This is so because, reflection of a preimage unto an image is a form of rigid transformation, therefore, the effect of the transformation operation will be similar when each point is individually considered.
Step-by-step explanation:
Given:
The figure of a right angle triangle.
To find:
The value which is equal to r÷q.
Solution:
In the given right triangle, the length of the hypotenuse is q units.
For angle x degrees, perpendicular is p units and base is r units.
For angle y degrees, perpendicular is r units and base is p units.
In a right angle triangle,
![\sin \theta=\dfrac{Perpendicular}{Hypotenuse}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cdfrac%7BPerpendicular%7D%7BHypotenuse%7D)
![\cos \theta=\dfrac{Base}{Hypotenuse}](https://tex.z-dn.net/?f=%5Ccos%20%5Ctheta%3D%5Cdfrac%7BBase%7D%7BHypotenuse%7D)
So,
![\sin y=\dfrac{r}{q}](https://tex.z-dn.net/?f=%5Csin%20y%3D%5Cdfrac%7Br%7D%7Bq%7D)
![\cos x=\dfrac{r}{q}](https://tex.z-dn.net/?f=%5Ccos%20x%3D%5Cdfrac%7Br%7D%7Bq%7D)
Therefore, the value of r÷q is equal to siny or cosx. So, the correct option is C.
80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176
Answer:
dx/dt= 0.2608 at h= 3.1 m
Step-by-step explanation:
a is the length of the ladder. a=5
by pythagorus theorem
![x^2 = a^2-h^2](https://tex.z-dn.net/?f=x%5E2%20%3D%20a%5E2-h%5E2)
differentiating with respect to t we get
......1
The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom
At h= 3.1
x^2= 6^2-3.1^2 = 9.1×2.9
x= 5.1371 m
given ![\frac{dh}{dt} =-0.4](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%7D%7Bdt%7D%20%3D-0.4)
putting values in 1 to get dx/dt
.
dx/dt= 0.2608 at h= 3.1 m
Answer:
11.00
Step-by-step explanation:
1. Since he's trying to buy 2 pairs you can multiply 27.00 by 2 or you can just add 27.00+27.00 and will get 54.00
2. Subtract 65.00-54.00
3. and you'll get 11.00