$y = 4 + 4 x^{2}-2x^{3} Lets \ write \ it \ y = -2 x^{3} +4 x^{2} +4
$
The tangential line at a certain point is just the derivative so.
$y ' = -6 x^{2} +8x$ . At the point (1,6) we plug the x value in and get the slope at the point (y ' = 2)

The tangential line at that point is
y - 6 = 2(x - 1) (this is the answer)

6 0

3 years ago

Rewrite the expression in the form 2".<br> E

Vlad [161]

Answer:

z^ {8/5}

Step-by-step explanation:

$(z^{\frac{-4}{3})^{\frac{-6}{5} } \\We\ know\ that\ a^{(b)^c} = a^{bc}\\\\Hence, \\\\{z^{\frac{-4}{3})^{\frac{-6}{5}}\\}={z^{\frac{-4}{3}*\frac{-6}{5}\\}\\=z^{\frac{24}{15}}\\=z^\frac{8}{5}$

6 0

2 years ago

Write a word problem for this equation.<br> 10 lb - w = 3 lb

Luden [163]

Answer:

10 people buy slushies and the price of each is lb. They have already spent w on food. How much did they spend on slushies.

Step-by-step explanation:

7 0

3 years ago