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AnnyKZ [126]
3 years ago
5

Highschool Seniors - What is some advice you can give me for time management, homework and schoolwise? I am a high school freshm

an, have been homeschooled up until now, and I am struggling with time management.
Mathematics
1 answer:
KIM [24]3 years ago
5 0

for homework I would do half first and then just play little and then do the rest for school boys I would just try to remember everything that I know and put it all down on paper and then and then you're able to answer like a test you're having to write notes and stuff like that

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Please help me by answering this?
Dmitrij [34]

Answer:

180

Step-by-step explanation:

\frac{6}{2} x^{2} | \frac{8}{2}

192-12=180

8 0
3 years ago
83. 6 in a complex number
grin007 [14]

Answer:

83.6 is a real number

Step-by-step explanation:

Since 83.6 83.6 is a real number, it is the real part (a) of the complex number a+bi a + b i . A real number does not contain any imaginary parts, so the value of b b is 0 0 . The answer is 83.6+0i 83.6 + 0 i

5 0
4 years ago
What is 2a - 8a = 12 - 8a
kicyunya [14]
2a-8a=12-8a
now add 8a to both side and you get

2a= 12

divide both sides by 2 and you get

a=6
6 0
3 years ago
Read 2 more answers
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
7
Fofino [41]

Answer:

15:7

Step-by-step explanation:

you put the numbers in order first the number of on time trains to off time trains

5 0
1 year ago
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