Step-by-step explanation:
Perimeter of a rectangle = 2(L+W)
L is the length of the rectangle:
W is the width of the rectangle.
Given
Perimeter = 214feet
If the length is 41 ft longer than the width, then L = 41+W
Substitute L = 41+W into the formula:
P = 2(L+W)
214 = 2(41+W+W)
214 = 2(41+2W)
214 = 82+4W
4W = 214-82
4W = 132
W = 132/4
W = 33 feet
Since L = 41+W
L = 41+33
L = 74 feet
Hence the dimension of the field is 74ft by 33ft
<em>The width of the playing field is 33feet</em>
35 I had this for a test the answer is
Answer:
30°
Step-by-step explanation:
<h2>C. ΔQRS ≅ ΔGFE </h2>
ΔQRS ≅ ΔGFE because :
∠Q = ∠G = 55°( corresponding part )
∠R = ∠F = 60° ( corresponding part )
∠S = ∠E = 65° ( corresponding part )
QS = GE = 16 ( corresponding part )
Therefore , the correct answer is :-
<h3>C. ΔQRS ≅ ΔGFE </h3>
There is no figure.
but you can use A^2 + B^2 = C^2
C is your hypotenuse.
so if you have the other two lengths if you square them and add them you'll have C squared. So you'll have to find the square root of that number to actually find the length.
