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m_a_m_a [10]
3 years ago
11

The variables x and y are related proportionally. When x = 8, y = 14. Find y when x = 32.

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

y = 56

Step-by-step explanation:

given that x and y are proportional then

y = kx ← k is the constant of proportionality

to find k use the given condition y = 14 when x = 8

k = \frac{y}{x} = \frac{14}{8} = \frac{7}{4}, thus

y = \frac{7x}{4}

when x = 32

y = \frac{7(32)}{4} = 56


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hoa [83]

Answer:

Its equal to 1

Step-by-step explanation:

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2 years ago
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Someone help me please:)
IRISSAK [1]
Im not that good with these types of problems but i think it is b if my math is correct.
6 0
3 years ago
Explain please, I’ve been having trouble with this question
GuDViN [60]

Step-by-step explanation:

I didn't need the other angles, but right of the bat you can tell it's two right triangles back to back.

<em>y </em> has to be 90° , as you have noticed they already gave you 70° on the right side of the shape meaning if you were to add 90 which is why plus 70 what would that give you? 160.

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2 years ago
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Reil [10]

<u>Answer:</u>

9. x = 12

10. x = 31

<u>Step-by-step explanation:</u>

9. Corresponding angles are equal, so technically you can move that (7x - 20) to be diagonal with the (4x + 16). Along with the corresponding angle, diagonal angles are equal to each other. Therefore you can set (7x - 20) equal to (4x + 16) to find x.

7x - 20 = 4x + 16

Solve

3x - 20 = 16

3x = 36

x = 12

Therefore x is equal to 12

<u>Check:</u>

4(12) + 16

= 64

7(12) - 20

= 64

10. All angles in a triangle have to add up to 180 degrees. Therefore, you can write your equation like this:

x + 2x + 25 + 2x = 180

Combine like terms

5x + 25 = 180

Solve

5x = 155

x = 31

Therefore, x = 31.

<u>Check:</u>

31 + 2(31) + 25 + 2(31) = 180

31 + 62 + 25 + 62 = 180

180 = 180

<em>I hope this helps!!</em>

<em>- Kay :)</em>

<em />

8 0
2 years ago
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8. Find an equation in standard form for the ellipse with the vertical major axis of length 16 and minor axis of length 4
MA_775_DIABLO [31]

Hello,

If center is (0,0)

x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b

Here

a=2 ==> a²=4

b=8 ==> b²=64

\boxed{\dfrac{x^2}{4}+ \dfrac{y^2}{64}=1}\\

3 0
3 years ago
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