Find the equation of a line that passes through the point (-2,3) and has a gradient of 3.
1 answer:
Answer:
y = 3x+9
Step-by-step explanation:
The standard form of equation of a line is in the form y = mx + c
m is the gradient
c is the y intercept
Get the y-intercept
Substitute m = 3 and the point (-2, 3) into the formula y = mx+c
3 = 3(-2) + c
3 = -6+c
c = 3+6
c = 9
Get the required equation;
y = 3x + 9
Hence the required equation is y = 3x+9
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