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igomit [66]
3 years ago
6

Find the equation of a line that passes through the point (-2,3) and has a gradient of 3.

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

y = 3x+9

Step-by-step explanation:

The standard form of equation of a line is in the form y = mx + c

m is the gradient

c is the y intercept

Get the y-intercept

Substitute m = 3 and the point (-2, 3) into the formula y = mx+c

3 = 3(-2) + c

3 = -6+c

c = 3+6

c = 9

Get the required equation;

y = 3x + 9

Hence the required equation is y = 3x+9

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Hey guys I need help with this math exercise... can someone plz help me??!!! 20 points to win!!!
riadik2000 [5.3K]
$73.36
i worked it out .
7 0
3 years ago
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
2 years ago
How to write an area formula using the sides of the triangle a,b,c?
bearhunter [10]

Answer:

A=hb b/2

Step-by-step explanation:

area=height(sub)base times base divided by 2


4 0
3 years ago
A rectangular patio has a length of 12 1/2 feet and an area of 103 1/8 square feet. What is the width of the patio?
Rina8888 [55]
Length of the rectangular patio = 12 1/2 feet
                                                  = 25/2 feet
Area of the rectangular patio = 103 1/8 square feet
                                               = 825/8 square feet
Let us assume the width of the rectangular patio = x feet
 Then
Area of the rectangular patio = Length * Width
825/8 = (25/2) * x
25x/2 = 825/8
25x = (825 * 2)/8 feet
25x = 825/4 feet
x = 825/(4 * 25) feet
   = 33/4 feet
   = 8 1/4 feet
So the width of the rectangular patio is 8 1/4 feet. I hope the procedure is clear enough for you to understand.
6 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest hundredth.
valina [46]

Answer:

  • FIRSTLY GET THE AREA OF THE WHOLE CIRCLE BY USING FORMULA
  • pi \times r ^2
  • THEN AFTER THAT DIVIDE THE AREA BY 2
  • AFTER THAT UR ANSWER WILL COME

<em>PLEASE</em><em> </em><em>MARK ME AS BRAINLIEST</em><em> </em>

3 0
2 years ago
Read 2 more answers
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