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posledela
3 years ago
5

Sines/cosines please help!!!!

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0
I can help explain it if you PM me.
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Hi, I need help with this
skelet666 [1.2K]
The value of x in the traingle is 5
---
3 0
3 years ago
4/7 divided by 7/2?????
11Alexandr11 [23.1K]

Answer:

8/49

Step-by-step explanation:

4/7 ÷7/2

Copy dot flip

4/7 * 2/7

Multiply the numerators

4*2 = 8

Multiply the denominators

7*7= 49

numerator over denominator

8/49

8 0
2 years ago
Read 2 more answers
HELPPPPPP ASAP What is the length of the third side of the window frame below? (5 points) (Figure is not drawn to scale.) 58a 1)
ollegr [7]

Answer:

The answer is 3) 40.

Step-by-step explanation:

since you're working with the Pythagorean theorem, you should know that a^2+b^2=c^2, therefore, we know that we only have two sides. we have a and c. we know that a = 42 and c = 58, giving us the equation of 42^2+b^2=58^2,

we want to find b!

so we would simply subtract the two.

58^2 - 42^2 = b

b = 1600

now we want to square root,

b = sqrt1600

which in the end, gives us the answer of 40.

4 0
2 years ago
Simplify completely:<br> 4V10 – V6 +3710<br> Show all work for full credit.
schepotkina [342]
The answer is 7√10−√6

5 0
3 years ago
Please help me thank you!
sergiy2304 [10]

Answer:

The equation of the line that passes through the points

(5,2) and (-5,6)

is

y=-2/5x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,2) and (-5,6).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=2.

Also, let's call the second point you gave, (-5,6), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=6.

Now, just plug the numbers into the formula for m above, like this:

m= 6 - 2/-5 - 5 or m= 4-10 or m=-2/5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-2/5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,2). When x of the line is 5, y of the line must be 2.

(-5,6). When x of the line is -5, y of the line must be 6.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-2/5x+b. b is what we want, the -2/5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,2) and (-5,6).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,2). y=mx+b or 2=-2/5 × 5+b, or solving for b: b=2-(-2/5)(5). b=4.

(-5,6). y=mx+b or 6=-2/5 × -5+b, or solving for b: b=6-(-2/5)(-5). b=4.

3 0
2 years ago
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