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3 years ago

Sines/cosines please help!!!!

Mathematics

1 answer:

AleksandrR [38]3 years ago

8 0

I can help explain it if you PM me.

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Five more than the product of four and a number is equal to the product of three and that same number increased by six.

svetlana [45]

Answer:

The number is 1.

Step-by-step explanation:

If you simplify the equation, it goes to 4x+5=3x+6. Subtract 5 from both sides and you get 4x= 3x+1. The only number that satisfies that equation is 1.

8 0

3 years ago

Read 2 more answers

Max has just won some money on a game show! He has the option to take a lump sum payment of $500,000 now or get paid an annuity

Fofino [41]

Answer:

The second option annually

Step-by-step explanation:

(4,900×12)×10 the multiply by 2.9%. Take that number and add on every 10 years

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3 years ago

A test is worth a total of 150 points and contains 70 questions. Some of the questions are worth 2 points and some are worth 4 p

GarryVolchara [31]

Answer:

$46 \times 2 = 92 \: points \\ 100 - 92 = 8 \: points \\ 4 \times 2 = 8 \\ two \: of \: the \: 4 \: points \: questions \: \\ were \: answered \: correctly$

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2 years ago

F(x) = -x^2<br> Find f(3)

Lemur [1.5K]

Answer:

Step-by-step explanation:

f(x) = -x^2

f(3) = -3^2

f(3) = 9

5 0

3 years ago

In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi

Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n = 50

sample mean $\overline x$ = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

$X \sim N ( \mu \sigma)$

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})$

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})$

$P(X>140) = 1 - P( Z\leq0.42)$

From z tables,

$P(X>140) = 1 - 0.6628$

$P(X>140) = 0.3372$

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

$Y \sim Binomial (np)$

$Y \sim Binomial (50,0.3372)$

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

$P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49} + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +... + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}$

P(Y ≥ 15) = 0.763

7 0

3 years ago