Hey there!
Since it's 30n, 30 is the coefficient and it's being multiplied by n.
We plug in n.
30(2) =
60
Hope this helps!
Answer: The length is 22 feet. The width is 4 feet.
Step-by-step explanation: Create an equation for the length: 2+5w=52.
Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.
So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)
Answer:

Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:

So, in
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
The determinant is:



Answer:
24
Step-by-step explanation:
There are 4 possibilities for the first card.
After that, there are 3 possibilities for the second card.
Finally, there are 2 possibilities for the third card.
The total number of permutations is 4×3×2 = 24.
Here's the list (in alphabetical order):
ARS
ART
ASR
AST
ATR
ATS
RAS
RAT
RSA
RST
RTA
RTS
SAR
SAT
SRA
SRT
STA
STR
TAR
TAS
TRA
TRS
TSA
TSR