1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GREYUIT [131]
3 years ago
6

the correct mixture of oil to gas in a weed eater is 1/2 pint of oil to 2 1/2 gallons of gas. how many pints of oil are needed f

or 10 gallons of gas?
Mathematics
2 answers:
Stells [14]3 years ago
8 0
This requires 2 pints of oil.

Using a proportion to solve this, we have:
\frac{\frac{1}{2}}{2\frac{1}{2}}=\frac{x}{10}

Cross multiplying, we have
1/2*10 = (2 1/2)*x
5 = (2 1/2)x

Divide both sides by 2 1/2:
5÷(2 1/2) = (2 1/2)x÷(2 1/2)
2 = x
masha68 [24]3 years ago
8 0

This needs 2 pints of oil.

You might be interested in
Bill and his classmates completed 14 activities in 4 hours. what is the unit rate at which they ocompleted the activities
uranmaximum [27]

Step-by-step explanation:

we first divide fourteen by four

14/4= 3.5

then we change 0.5 to hours by multiplying by 60

0.5 * 60 = 30

so in conclusion it would take 3hrs 30mins to finish each activity

8 0
2 years ago
A partial proof was constructed given that MNOP is a parallelogram.
Elena-2011 [213]

Answer:

B

Step-by-step explanation:

B. angle N is supplementary to angle P

4 0
3 years ago
Read 2 more answers
In a G.P., the third term exceeds the first term by 16.
Tresset [83]

Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

Then,

a(r-1)(r+1)=16. Equation 2

Divide equation 2 by equation 1

a(r-1)(r+1)/ar^2(1+r) =16/72

Then a cancel a and (1+r) cancel (1+r)

So,

(r-1)/r^2=2/9

Cross multiply

9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

Then r=3 or r=3/2

8 0
3 years ago
Solve 13x=91 plzz I need it ASAP
boyakko [2]

Answer

7

Step-by-step explanation:

13x=91

91/13=x

x=7

8 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answers as radicals in simplest form.
Citrus2011 [14]

This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 1:1:\sqrt{2} so we get


u = v =  8


We could have also gotten this using Trig:


u = (8 \sqrt{2}) \sin 45^\circ = 8 \sqrt{2}/\sqrt{2} = 8


v = (8\sqrt{2})\cos 45^\circ = 8


Or by recognizing u=v because remaining angle is 45 so this must be isosceles so


u^2 + u^2 = (8 \sqrt{2})^2


2u^2 = 2 (8^2)


u = 8

8 0
4 years ago
Other questions:
  • Twice the difference of a number and 3 equals 8
    5·2 answers
  • What is the value of the following expression? <br> -9/4➕-8/5-2 1/2
    15·1 answer
  • Sally has a credit card balance of ​$10,000. The credit card company charges a nominal interest rate of 17 percent a year on unp
    13·1 answer
  • (3.9 x 10^2)(2.3 x 10^6)
    12·1 answer
  • Find the GCF of each pair of monomials 60jk, 45jkm
    14·2 answers
  • Select the correct difference.<br> -3z 5 - (-7z 5)
    11·1 answer
  • The value of y varies directly with x, when y = 5 and x = 6. What is the equation for this relationship? What is the value of y
    13·2 answers
  • 20 is 80 percent of what number?
    11·2 answers
  • Five weeks after the introduction of a new toy, the manufacturer found that the demand for the toy was modeled by f(x) = x^2 +5x
    7·1 answer
  • Someone help please thanks.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!