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Alex_Xolod [135]
3 years ago
9

T(3,-5) ABCD = A’B’C’D’. What translates A’B’C’D’ back to ABCD?

Mathematics
1 answer:
Tom [10]3 years ago
7 0

A’B’C’D’ is obtained by translating ABCD 3 units to the right (i.e. a positive translation of 3 units along the x axis) and 5 units down (i.e. a negative translation of 5 units along the y axis).

So, in order to go back to ABCD, we have to invert both translation: we have to go 3 units to the left (i.e. a negative translation of 3 units along the x axis) and 5 units up (i.e. a positive translation of 5 units along the y axis).

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Georgia [21]

See picture for a reply to your question.



4 0
3 years ago
Consider the scatter plot.
julia-pushkina [17]

Answer:

A

Step-by-step explanation:

An outlier is a data point that seems like it shouldn't belong; it could be extremely small or extremely big or simply not even a part of the correlation.

Looking at the scatter plot, it's quite clear that there is one point far from the others. This will be the outlier.

Observe its coordinates; they are about (8.8, 5.2).

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Hope this helps!

5 0
3 years ago
Read 2 more answers
If another line is perpendicular to the line shown on the graph, what must be its slope
Shtirlitz [24]

It's B

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m1 = -2/5

The diagram shows a gradient of -2/5. So, the

reciprocal of this valve to make - 1 is 5/2 (which is the - 2/5 flipped upside down, but positive)

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Thus, the perpendicular line to this has a gradient of 5/2.

Hope this helps!

4 0
2 years ago
Assume that the pond contains 90 fish: 64 purple, 25 green, and 1 red. A contestant pays $0.55 to randomly catch one fish and re
Licemer1 [7]

Answer:

The carnival is losing (on average) $0.15 on each play

Step-by-step explanation:

To find out how much the carnival wins or looses in each play one subtract the expected value (EV) from each play from the amount charged by the carnival for each play ($0.55). If the expected value is higher than what the carnival charges, the carnival is losing money.

Expected is the sum of the payouts of each bet multiplied by its likelihood:

EV= \frac{64*0.40+25*1.15+1*9.00}{90}\\EV= 0.70

Since the expected value is higher than $0.55, the carnival is losing money, on average, on each play:

0.55-0.7 = -0.15

The carnival is losing (on average) $0.15 on each play

6 0
3 years ago
I will give BRAINLIEST to whoever is CORRECT
8090 [49]
I believe the answer could be 

h = -16t^2 + 32t + 12
      ---------------------------
                    t<span />
7 0
4 years ago
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