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3 years ago

3/4 x - 2/3 less than or equal to 5/6

Mathematics

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

The solution is:

$\frac{3}{4}x-\frac{2}{3}\le \frac{5}{6}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:2\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:2]\end{bmatrix}$

The solution graph is also attached.

Step-by-step explanation:

Given the expression

' 3/4 x - 2/3 less than or equal to 5/6 '.

In inequality, the phrase 'less than or equal' is represented as ' ≤ ''.

Thus, the expression is

$\frac{3}{4}\:x\:-\:\frac{2}{3}\:\:\le \frac{5}{6}\:$

Add 2/3 to both sides

$\frac{3}{4}x-\frac{2}{3}+\frac{2}{3}\le \frac{5}{6}+\frac{2}{3}$

Simplify

$\frac{3}{4}x\le \frac{3}{2}$

Multiply both sides by 4

$4\cdot \frac{3}{4}x\le \frac{3\cdot \:4}{2}$

$3x\le \:6$

divide both sides by 3

$\frac{3x}{3}\le \frac{6}{3}$

Simplify

$x\le \:2$

Therefore, the solution is:

$\frac{3}{4}x-\frac{2}{3}\le \frac{5}{6}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:2\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:2]\end{bmatrix}$

The solution graph is also attached.

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How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6

Ivahew [28]

$9\cos(2t)=6\implies\cos(2t)=\dfrac23$

Using the fact that cos is 2π-periodic, we have

$\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi$

That is, $\cos(\theta+2n\pi)=\cos\theta$ for any $\theta$ and integer $n$ .

$\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi$

We get 2 solutions in the interval [0, 2π] for $n=0$ and $n=1$ ,

$t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi$

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3 years ago

Please can anyone help???

marta [7]

Answer:

x = -3, y = 0

Step-by-step explanation:

15 - 9 = 6

6 - 9 = -3

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3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

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Answer: See explanation

Step-by-step explanation:

Total marks = 60

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Priya gets a silver medal

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