For distance in 1 minute, divide the distance for 6 minutes by 6 minutes:
7.5 km / 6 minutes = 1.25 km per minute.
For 100 minutes, multiply distance per minute by total minutes:
1.25 km per minute x 100 minutes = 125 km
You should use 12$ per because your overall profit was higher. Lower cost means less profit but higher number of buyers
7x8÷4x37x8÷4x3 = 3108/1 = 3108
Answer:
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
Step-by-step explanation:
Let the random variable Y have a geometric distribution g (y;p) = pq y-¹
The m.g.f of the geometric distribution is derived as below
By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)
= pe^t ∑(e^tq)^y-1
= pe^t/1- qe^t, where qe^t <1
In order to differentiate the m.g.f we write it as
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
M₀` (t) = pe^-t (e^-t -q) ^ -2 and
M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2
Hence
E (y) = p (1-q)-² = 1/p
E (y²) =2 p (1-q)-³ - p (1-q)-²
= 2/p² - 1/p and
σ² = [E (y²) -E (y)]²
= 2/p² - 1/p - (1/p)²
= q/p²
Answer:
The answers are;
a. The probability of more than one death in a corps in a year is 0.12521.
b. The probability of no deaths in a corps over five years is 4.736 × 10⁻².
Step-by-step explanation:
For Poisson Distribution we have
Pₓ(k) =
Where:
λ = Mean per unit time
k = Specified data point
t = time
e = Euler constant
a. The probability of more than one death in a corps in a year is given by
The mean of the Poisson distribution for one year is given as
λ·t = 0.61 × 1 = 0.61
Therefore by using complement principle, we have
P (X >1) = 1 - P(X = 0) - - P(X = 1)
=1- -
= 1 - 0.543 - 0.3314
= 0.12521
b. Here we have t = 5
Therefore the mean = λ·t = 0.61×5 = 3.05
The probability of there being no deaths in a corps for over five years is
P (X =0) = = 4.736 × 10⁻²
The probability is 4.736 × 10⁻² .