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Nutka1998 [239]
3 years ago
6

Can someone help me with this question please! 5-x=12

Mathematics
2 answers:
alisha [4.7K]3 years ago
3 0

Answer:

x=-7

Step-by-step explanation:

Subtract 5 from both sides.

−x=12−5

Subtract 5 from 12 to get 7.

−x=7

Multiply both sides by −1.

x=−7

dezoksy [38]3 years ago
3 0

Answer:

x = -7

Step-by-step explanation:

When subtracting negative numbers from positive it's like adding. The rules are a bit wonky I know haha. So your problem would look like this when "x" is solved:

5 - -7 = 12

<u>Hope this helps and have a nice day!</u>

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denis-greek [22]

Answer:

4 is the median to your problem

8 0
3 years ago
Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.
Anna [14]

Answer:

a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

If

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

<h2>a.</h2>

(2, 1) and (4, 5)

m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}

<h2>b.</h2>

(-1, 0) and (3, -5)

m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}

<h2>c.</h2>

(2, 1) and (-3, 1)

m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}

<h2>d.</h2>

(-1, 2) and (-1, -5)

m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}

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wlad13 [49]

Answer:

The center of the circle is C(x,y) = (2, 3).

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y) (1)

Where:

C(x,y) - Center.

R_{1} (x,y), R_{2} (x,y) - Location of the endpoints.

If we know that R_{1} (x,y) = (-2,10) and R_{2} (x,y) = (6,-4), then the location of the center of the circle is:

C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)

C(x,y) = (-1, 5) + (3, -2)

C(x,y) = (2, 3)

The center of the circle is C(x,y) = (2, 3).

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Answer:

sorry I don't know the answer

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