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stiv31 [10]
3 years ago
6

Given V = 24h, solve for h

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0

Good evening ,

______

Answer:

V = 24h Then h = V÷24.

:)

Lelu [443]3 years ago
5 0

V=24h

divide by 24 for both sides

V/24= 24h/24

Cross out 24 and 24, divide by 24 and then becomes 1*1*h= h

Answer: h= V/24

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Art [367]

Answer:

I WISH I COULD BUT I'm IN 4TH GRADE

3 0
3 years ago
What is 0.08 into a fraction
spayn [35]

Answer is provided in the image attached.

6 0
3 years ago
3. The path of an underground stream is given by the function y = 4x² +17x -32. Two
sineoko [7]

Answer:

The coordinate of the wells are

(-4 -\sqrt[]{\frac{53}{2}}, 70+15\sqrt[]{\frac{53}{2}})

(-4 +\sqrt[]{\frac{53}{2}}, 70-15\sqrt[]{\frac{53}{2}})

Step-by-step explanation:

The y coordinate of the stream is given by y = 4x^2+17x-32. Also, the y coordinate of the houses are determined by y=-15x+10. We will assume that the houses are goint to be built on the exact position where we build the wells. We want to build the wells at the exat position in which both functions cross each other, so we have the following equation

4x^2+17x-32 = -15x+10

or equivalently

4x^2+32x-42=0 (by summing 15x and substracting 10 on both sides)

Dividing by 2 on both sides, we get

2x^2+16x-21=0

Recall that given the equation of the form ax^2+bx+c=0 the solutions are

x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}

Taking a =2, b = 16 and c = -21, we get the solutions

x_1 = -4 -\sqrt[]{\frac{53}{2}}

x_2 = -4 +\sqrt[]{\frac{53}{2}}

If we replace this values in any of the equations, we get

y_1 = 70+15\sqrt[]{\frac{53}{2}}

y_2 = 70-15\sqrt[]{\frac{53}{2}}

4 0
3 years ago
Can you please help me I would appreciate it so much
dmitriy555 [2]

Answer:

Below.

Step-by-step explanation:

The distributive property:

3(x + 4)

= 3*x + 3*4

= 3x + 12.

You are ' distributing 3 over the parentheses'

6 0
3 years ago
Is 890,353 mL bigger than 89 L 353mL
Gemiola [76]
Yes, because 89L = 89,000ml. So 89L 353mL = 89,353mL. Thus, 890,353mL is greater.
5 0
3 years ago
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