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2 years ago

1st shape has a 4 2nd shape has a 6 pls help-T T I don’t know how to do this-

Mathematics

1 answer:

docker41 [41]2 years ago

4 0

Answer:

2.5

Step-by-step explanation:

because you can tell by the numbers and how close they are then u have to divide

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Help help help math math

Rina8888 [55]

Answer:

100 cm³

Step-by-step explanation:

If you use 3 for π, then the factors of 3 cancel in the formula for volume, and you have ...

V = r²h

The radius is half the diameter, so is (10 cm)/2 = 5 cm. Filling in the given values, you find the volume to be ...

V = (5 cm)²(4 cm) = 100 cm³

7 0

1 year ago

Jeremiah is making monthly payments of $66.00 to pay off a loan that he took out to buy a drum set, But he wants to pay off his

dsp73

I don't believe all of the information is given but I would say off the information that is provided it would be $70.00 per month

7 0

2 years ago

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Which is the contrapositive of the conditional statement?

Elena L [17]

The answer is "If it does not have four legs, then an animal is not a deer."

To form the contrapositive, switch the hypothesis and the conclusion and negate both.

The hypothesis is the "if" part and the conclusion is the "then" part.

7 0

2 years ago

Find the value of x.<br> 48°<br> (7x + 13)

Pavel [41]

Answer:

336x + 624

Step-by-step explanation:

4 0

2 years ago

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

2 years ago

Read 2 more answers