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Luda [366]
3 years ago
15

Jamie completes the following steps in an experiment to investigate how temperature affects how fast something will rust in wate

r. He places a nail in a bowl of water in the sun and a nail in a bowl of water in the shade. He also leaves an iron nail out of the water in a dry bag out of the sun. Why would Jamie leave one out of the water and out of the sun?
A Jamie also wants to test if the water affects how fast the iron nail will rust.
B Jamie notices that the size of the nail is different, so he does not want to use it later.
C Jamie doing all these steps to create a control group to compare his results to.
D Jamie puts the nail in a cooler place to see if it will rust as fast as the other items.
Chemistry
2 answers:
stiks02 [169]3 years ago
6 0
B. Jamie notices that the size of the nail is different, so he does not want to use it later
earnstyle [38]3 years ago
5 0

Answer:

I think B

Explanation:

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4 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
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Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
4 years ago
*aluminium ,chromium manganese are all moderately reactive metals use the following information to arrange them in the correct r
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The order:

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viktelen [127]

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Explanation:

Hello!

In this case, for the given chemical reaction, we can see there is a 1:4 mole ratio between tetraphosphorous decaoxide and phosphorous; therefore, the following proportional factor provides the requested moles of phodphorous:

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Answer:

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I am not to sure if this is correct, but I hope it helps in some way.

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