Answer:

Explanation:
The atomic weight of oxygen = 15.9994 g
This mass corresponds to 1 mole of the oxygen atoms.
Thus,
15.9994 g mass of oxygen contains
atoms of oxygen.
1.4 kg = 1400 g ( 1 kg = 1000 g)
So,
1400 g mass of oxygen contains
atoms of oxygen.
Number of atoms in 1400 g of oxygen = 
Also, 1 atom of oxygen contains 8 protons
Charge of 1 proton = + 
So, Charge on 1 atom of oxygen = 
Thus,
Charge on
atoms of oxygen = 
Thus, positive charge in 1.4 kg of oxygen = 
REACTION TYPE:
Single displacement/Oxidation-reduction
(Hope this helped UwU)
Answer:

Explanation:
Here, we want to get the volume of the nitrogen gas at the lower temperature
From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion
The mathematical relationship is:

Where:
V1 is the initial volume which is 410 L
V2 is the final volume which is unknown
T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K
T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K
Substituting the values, we have it that:
Explanation:
Entropy means the amount of randomness present within the molecules of the body of a substance.
Relation between entropy and microstate is as follows.
S = 
where, S = entropy
= Boltzmann constant
= number of microstates
This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.
Also, let us assume that
= 1, and
= 0.833
Therefore, change in entropy will be calculated as follows.

= 
= 
= 
or, = 
Thus, we can conclude that the entropy change for a particle in the given system is
J/K particle.
Answer:
Major product ethoxide ion
Explanation:
- Sodium hydride acts as a strong base towards ethanol.
- Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
- It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
- Structure of major organic product i.e. ethoxide ion has been shown below.