Answer:
Actual yield = 0.1791 moles
Theoretical yield in moles = 0.644 moles
Percent yield = 27.8 %
Explanation:
The formula for the calculation of moles is shown below:
Given: For Fe
Given mass = 10.0 g
Molar mass of Fe = 55.845 g/mol
Moles of Fe = 10.0 g / 55.845 g/mol = 0.1791 moles
So, Actual yield = 0.1791 moles
Given, Moles of = 0.322 moles
According to the given reaction:
1 mole of on reaction produces 2 moles of Fe
0.322 mole of on reaction produces 2*0.322 moles of Fe
Actual moles of Fe produced = 0.644 moles
Theoretical yield in moles = 0.644 moles
Or, Mass of iron = Moles × Molar mass = 0.644 × 55.845 g = 35.96 g
Theoretical yield = 35.96 g
Given experimental yield = 10.0 g
% yield = (Experimental yield / Theoretical yield) × 100 = (10.0/35.96) × 100 = 27.8 %