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3 years ago

How is matter and energy conserved when liquid is frozen

Chemistry

1 answer:

Brut [27]3 years ago

3 0

Answer:

The big energy change when water freezes is in the potential energy of interactions between the water molecules.

Explanation:

I am not to sure if this is correct, but I hope it helps in some way.

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A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil

Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V $_1$ ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V $_1$ ) = 1.50 L,

Initial moles ( n $_1$ ) = 3.00 mol,

Final Volume ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V $_2$ ).

P $_1$ V $_1$ / n $_1$ T $_1$ = P $_2$ V $_2$ / n $_2$ T $_2$ - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V $_1$ / n $_1$ = V $_2$ / n $_2$ - isolate V $_2$ ,

V $_2$ = V $_1$ n $_2$ / n $_1$ = 1.50 L $*$ 2.5 mol / 3.00 mol = ( 1.5 $*$ 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0

3 years ago

Which process of making a stainless steel product does the photograph

Delvig [45]

It would be B, combining

5 0

2 years ago

Read 2 more answers

Complete the nuclear equation

allsm [11]

In order to solve this question, we must apply the conservation of mass. The total number of nucleons (upper number) and protons (lower number) must be equal before and after the decay. The new nucleon number is
218 - 4
= 214
And new proton number is
84 - 2
= 82
Next, we must identify which element has the proton number 82. That would be lead, Pb.
Therefore, the answer is
5. ²¹⁴Pb₈₂

5 0

3 years ago

At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu

mariarad [96]

According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M

7 0

3 years ago

replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Calcul

Fantom [35]

The difference between the wattage is 60-18=42W. The saving in energy over 10 hrs is 10×42=420 watt-hours=0.42kWh

8 0

2 years ago