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3 years ago

How is matter and energy conserved when liquid is frozen

Chemistry

1 answer:

Brut [27]3 years ago

3 0

Answer:

The big energy change when water freezes is in the potential energy of interactions between the water molecules.

Explanation:

I am not to sure if this is correct, but I hope it helps in some way.

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Need help plz asap .......

olganol [36]

Answer:

Purple flowers

Explanation:

Usually the dominant allele is a capital letter.

From the question, purple flowers are dominant to white flowers while white are recessive.

PP = Purple

pp = White

4 0

2 years ago

Read 2 more answers

10 atoms of Hydrogen and 5 atoms of Oxygen would make molecules of water.

steposvetlana [31]

Answer:

No, it won't. Because water is made up of two atoms of hydrogen and an atom of oxygen (the composition of water).So now do you understand? Text me if you do/don't for more explanation. Thanks for asking

7 0

3 years ago

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens

poizon [28]

Answer:

It increases by a factor of four

Explanation:

Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.

pV = K.......(1)

pV = constant

Charles law : The volume of the gas is directly proportional to temperature at constant pressure.

V = KT

or V/T = K = constant ....(2)

Applying equation (1) and (2)

$\frac{PV}{T}=K$

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

According to question ,

T2 = 4 (T1)

V2 = V1

Put the value of T2 and V2 , The P2 can be calculated,

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{4T_{1}}$

V1 and V1 cancel each other

T1 and T1 cancel each other

We get,

$P1=\frac{P2}{4}$

P2 = 4 P1

So pressure increased by the factor of four

5 0

3 years ago

A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam

Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0

3 years ago

Which is the correct Lewis dot structure of NH2? A.A B.B C.C D.D E.E

Anarel [89]

I think D is your answer

5 0

2 years ago

Read 2 more answers