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Rudik [331]
2 years ago
7

How much of the water (in ml ) contains 150 mg of pb ? (assume a density of 1.0 g/ml .)

Chemistry
1 answer:
NARA [144]2 years ago
5 0

There are 0.15 ml of the water contains 150 mg of Pb .

Calculation ,

Formula used :

density = mass / volume                 ( i )

Given mass of the Pb in milligram ( mg ) = 150 mg

Given mass of the Pb in gram ( g ) = 150 × 10^{-3} = 0.15 gram

Given density = 1.0 g/ml

We have to find volume of water in milliliter ( ml ) .

Putting the value of mass of the Pb , lead and density in equation ( i ) we get the volume of water in milliliter ( ml ) .

density = mass / volume

1.0 g/ml  =  0.15 gram / volume

volume =  0.15 gram / 1.0 g/ml = 0.15 ml

To learn more about density please click here ,

brainly.com/question/15164682

#SPJ4

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They come from the Sun.
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3 years ago
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Study the reaction. NO(g) ⇌ 12N2(g) + 12O2(g) ΔH = −90.3 kJ Which statement about the reaction is correct? A) The reverse reacti
lozanna [386]

Answer:

The forward reaction is an exothermic reaction.

Explanation:

An exothermic reaction is one in which energy is released, usually in the form of heat hence the enthalpy of the reaction is negative. When a reaction exothermic, the energy of the reactants is greater than the energy of the products hence the excess energy is given out as heat. The reactants lie at a higher energy level in the reaction profile compared to the products.

When we look at the reaction given in the question, NO(g) ⇌ 12N2(g) + 12O2(g) ΔH = −90.3 kJ , we can easily see from the thermochemical reaction that the forward reaction is exothermic, energy is released by the reaction system as evidenced by the negative enthalpy of reaction.

4 0
3 years ago
Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2 is 7.
murzikaleks [220]

Answer: The rate of the loss of O_3 is 0.52M/s

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

2O_3(g)\rightleftharpoons 3O_2(g)

Rate of disappearance of O_3 =-\frac{1d[O_3]}{2dt}

Rate of formation of O_2 =+\frac{1d[O_2]}{3dt}

-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}

Rate of formation of O_2 = 7.78\times 10^{-1}M/s

Thus Rate of disappearance of O_3 =\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s

8 0
3 years ago
Estructura correcta de los siguientes compuestos e indique si el nombre está escrito de forma correcta; 1,4-ciclohexadieno
Makovka662 [10]

Answer:

En la imagen adjunta.

Explanation:

¡Hola!

En este caso, dados los lineamientos IUPAC que tenemos en cuenta para dibujar la estructura de hidrocarburos cíclicos, para el 1,4-ciclohexadieno, es posible determinar que esta estructura viene dada por hexágono que representa el ciclohexano y dos dobles enlaces en los carbonos 1 y 4 al ser un dieno. Por lo anterior, en la imagen adjunta, puede encontrar la estructura requerida.

¡Saludos!

5 0
3 years ago
can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ
mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

7.SL

8.CL

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10.CL

Explanation:

HOPE ITS HELP

5 0
3 years ago
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