Question

How much of the water (in ml ) contains 150 mg of pb ? (assume a density of 1.0 g/ml .)

Answer 1

There are 0.15 ml of the water contains 150 mg of Pb .

Calculation ,

Formula used :

density = mass / volume                 ( i )

Given mass of the Pb in milligram ( mg ) = 150 mg

Given mass of the Pb in gram ( g ) = 150 × $10^{-3}$ = 0.15 gram

Given density = 1.0 g/ml

We have to find volume of water in milliliter ( ml ) .

Putting the value of mass of the Pb , lead and density in equation ( i ) we get the volume of water in milliliter ( ml ) .

density = mass / volume

1.0 g/ml  =  0.15 gram / volume

volume =  0.15 gram / 1.0 g/ml = 0.15 ml

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