Unit test

victor has the map scale missing.he knows the distance from the lake to the youth center is 8 miles. on the map they are 2in. ap

kupik [55]

The correct scale is 1 in = 4 mi.

Explanation:

The scale tells us what a given measurement on the map equals in real-life distance.

The measurement on the map that we have is 2 inches, and it equals 8 miles:

2 in = 8 mi

This can also be written as 2/8. This fraction can be simplified, since both 2 and 8 are divisible by 2; it will simplify to 1/4. This is the same as
1 in = 4 mi.

6 0

3 years ago

Read 2 more answers

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable X as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

Thus, the expected value of the temperature increase is 17.5°C.

7 0

3 years ago

Find the value of x. x, 50, and 70

Rama09 [41]

X = 60°

To work this out, you would do 50°+70° to get 120°. You would then subtract this from 180° (the total for any triangle) to get the final answer of 60°.

5 0

3 years ago

What is the product?

victus00 [196]

Answer:

$\begin{bmatrix}-2\\0 \end{bmatrix}$