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2 years ago

Unit test

Mathematics

1 answer:

Fed [463]2 years ago

3 0

Answer : 32
Solution: none

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Find the shaded region.

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Answer:

Step-by-step explanation:

let the side of outer square=2x

then x²+x²=(20√2)²

2x²=800

x²=400

x=√400=20 in

2x=2×20=40 in

area of outer square=40²=1600 in²

area of inner square=(20√2)²=800 in²

area of shaded region A=1600-800=800 in²

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3 years ago

The area of a classroom space per student varies inversely with the number of students in the room. When there are 15 students i

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You would times 20 and 15 to get 300 and then divide 300 by 25 to get 12

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Catherine walks her dog 3/4 mile everyday how far does she walk each week

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Catherine walks her dog 5.25 miles because there are 7 days in one week and 3/4 x 7 = 5.25

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Lisa took a survey of her classmates' favorite sport and recorded their genders. The results are in the table below:

Igoryamba

Answer:

0.43

Step-by-step explanation:

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2 years ago

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

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2 years ago