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lorasvet [3.4K]
2 years ago
13

Please help! Will give brainliest :)

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
7 0

Answer:

15 boys in 3 groups

15 girls in 4 groups

Step-by-step explanation:

60 ÷ 4 = 15

45 ÷ 3 = 15

Have an awesome day! :D

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if you have 20 yards of ribbon and need to vut it into 2 yard lengths how many cuts do you have to make. step by step if u can i
wlad13 [49]

Answer:

10

Step-by-step explanation:

Given: 20 yards of ribbon in total. Need to make 2 yards each.

To find out how many yards you need to cut, divide:

20 / 2 = 10

So, you need to make 10 cuts for the 20 yards.

Hope this helped.

7 0
2 years ago
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The Drop Rate Of A Item Is 0.01% to get one, but there are 2 other items with the same drop rate. so there are 3 items with a dr
Bumek [7]

Answer:

If you hope to get the rare Deathcharger's Reins mount from Baron Rivendare for example, we know that it has a 1% drop chance. That means that every time you kill the Black Baron you have a 1% chance of getting the mount. 1% on the first kill, and 1% on the 100th kill. However, over the course of 100 kills, you have a much higher probability of getting the mount. But not 100%. Never 100%.

Step-by-step explanation:

5 0
3 years ago
Chose all the correct answers.
Aleksandr-060686 [28]
Scalene I believe. Hope this helps!
8 0
3 years ago
Read 2 more answers
I need help please !!
Lubov Fominskaja [6]

Answer:

B

Step-by-step explanation:

Isolate a

f = m × a

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3 0
3 years ago
Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t
Elden [556K]

Answer:   a) \bold{\dfrac{3}{16}}     b) \bold{\dfrac{1}{36}}

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even     \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

2) Even, Even, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

3) Odd, Odd, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

<em>Order doesn't matter</em>

Add them up to get your answer: \dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}

3 0
3 years ago
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