The value of x is 1.14 or x = -1.47
We find the value of x in the quadratic equation 3x^2 +x-5=0
Using the formula: (-b ± √ (b²- 4 a c)) / (2a)
Where the value of a = 3, b = 1 and c = -5
Substituting the above values (a = 3, b = 1 and c = -5)
in the formula:
(-1 ± √ (1²- 4 3 (-5))) / (2*3)
= (-1 ± √ (1+60)) / (6)
= (-1 ± √ (61)) / (6)
= (-1 ± 7.81) / (6)
= (-1 + 7.81) / (6) or (-1 -7.81) / (6)
= (6.81) / (6) or (-8.81) / (6)
=1.135 or -1.468
Hence the value of x= 1.14 or -1.47
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To find the speed you must write S= d/t so for the first one we will chang 15 m to b so it is = 0.25h so s=3/0.25h = 12km/h an why secand is 45 m to h = 0.75h so S=d/t S =12/0.75 =16 km/h the to find the totel speed we should + the speed together so 12 + 16 = 28 km/h
Answer:
6) c
7) d
Step-by-step explanation:
6) 25 + 15= 40
40+35=75
Php. 75
7) 29•3=87
150-87=63
Php. 63
Hope this helps!
Answer:
5x
Step-by-step explanation:
I think the problem was.
3(3x - 2y) - (4x - 6y)
9x - 6y - 4x + 6y
5x
Answer:
Step-by-step explanation:
We are given that:
And we want to find F'(0).
First, find F(x):
![\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20f%283x%29%5D)
From the chain rule:
![\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20F%27%28x%29%20%26%3D%20f%27%283x%29%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cleft%5B%203x%5Cright%5D%20%5C%5C%20%5C%5C%20%26%3D%203f%27%283x%29%5Cend%7Baligned%7D)
Then:
In conclusion, F'(0) = 15.
