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CaHeK987 [17]
3 years ago
7

Please help me please it is hard

Mathematics
2 answers:
Arturiano [62]3 years ago
3 0
Which one first show me your problem
Inessa05 [86]3 years ago
3 0
What's the question? Didn't show up
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Stion<br> Factor the difference of squares.<br> x2 - 400<br> The factored form of x2 - 400 is
Sloan [31]

Answer:

The factored form of x²-400 is (x+20)(x-20).

Step-by-step explanation:

Given the expression

x^2\:-\:400

As the square of 20 is 400. Therefore, rewrite 400 as 20²

⇒ x^2-20^2

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

Thus, the expression becomes

x^2-20^2=\left(x+20\right)\left(x-20\right)

Thus, the factored form of x²-400 is (x+20)(x-20).

3 0
3 years ago
I need help, I need to find the volume of this
Paladinen [302]

Answer:

<h2><u><em>396 Km³</em></u></h2><h2><u><em>to the nearest hundred</em></u></h2><h2><u><em>400 Km³</em></u></h2>

Step-by-step explanation:

volume of a cuboid = Length × Width × Height Cubic units

6 × 11 × 6 =

66 * 6 =

396 Km³

to the nearest hundred

400 Km³

5 0
2 years ago
What does 4x+12x equal
Yuliya22 [10]

Answer:

16x

Step-by-step explanation:

4x+12x

Combine like terms

16x

8 0
3 years ago
Read 2 more answers
A new sales training program has been instituted at a rent-to-own company. Prior to the training, 10 employees were tested on th
Lunna [17]

Answer:

C. H0: µD = 0, HA: µD <0

Step-by-step explanation:

We assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. So for this case is better apply a paired t test.  

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value for pretest , y = test value for posttest  

x: 66, 94, 87, 84, 76, 88

y: 75, 100, 93, 85, 75, 90  

The system of hypothesis for this case are:  

Null hypothesis: \mu_D \geq 0  

Alternative hypothesis: \mu_D < 0  

Because the difference D is defined as Pretest-Postest. And we want to see if the postets score is higher than the pretest with th training.

The first step is calculate the difference d_i=x_i-y_i and we obtain this:  

d: -9, -6, -6, -1, 1, -2

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{-23}{6}=-3.833  

The third step would be calculate the standard deviation for the differences, and we got:  

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =3.763  

The 4 step is calculate the statistic given by :  

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-3.833 -0}{\frac{3.763}{\sqrt{6}}}=-2.494  

The next step is calculate the degrees of freedom given by:  

df=n-1=6-1=5  

Now we can calculate the p value, since we have a left tailed test the p value is given by:  

p_v =P(t_{(5)}  

The p value is lower than the significance level assumed \alpha=0.05, so then we can conclude that we can reject the null hypothesis. So we can say that the differences between Pretest and Posttest \mu_{pretest}-\mu_{postest} are less than 0.

3 0
3 years ago
Which of the following equations has an infinite number of solutions?
Inessa [10]
It is 3x +5 = 2x -1 + x 
i hope that is was some sort of help you are welcome 
5 0
3 years ago
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