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OLEGan [10]
3 years ago
11

Eliminate the decimal from 0.15/0.003

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0
The correct answer is 50
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If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?
Dominik [7]

Answer:

HJ=20\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The <u><em>intersecting chords theorem</em></u>  is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

so

In this problem

(RH)(HT)=(GH)(HJ)

substitute the given values

(10)(16)=(8)(HJ)

solve for HJ

HJ=160/8\\HJ=20\ units

7 0
3 years ago
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K= 1/2mv^2<br> Solve for V
jeyben [28]

Hi there!

v = ±\sqrt{\frac{2K}{m} }

- - - - - - - - -

K = 1/2mv²

Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):

2 · K = 2 · (1/2mv²)

2K = mv²

Continue isolating by dividing both sides by "m":

2K / m = v²

Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.

v = ±\sqrt{\frac{2K}{m} }

7 0
3 years ago
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Estimate <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B80%7D%20" id="TexFormula1" title=" \sqrt{80} " alt=" \sqrt{80} " ali
Tamiku [17]

Answer:

8.9

Step-by-step explanation:

Convert  √ 80  to a decimal.

8.9442719

Find the number in the tenth place  9  and look one place to the right for the rounding digit  4 . Round up if this number is greater than or equal to  5  and round down if it is less than  5 .

8 0
3 years ago
Giving brainliest for help plz
Kryger [21]

Answer is B.

Thanks!!

5 0
3 years ago
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-18 + 2a = 2(3a + 1)
Nadusha1986 [10]

Answer:

a = -5

Step-by-step explanation:

Given

-18 + 2a = 2(3a + 1)

Expand the bracket on the right

-18 + 2a = 2 x 3a + 2 x 1

-18 + 2a = 6a + 2

Add 18 to both sides

-18 + 18 + 2a = 6a + 2 + 18

2a = 6a + 20

Subtract 6a from both sides

2a - 6a = 6a - 6a + 20

-4a = 20

Divide both sides by -4

-4a/-4 = 20/-4

a = -5

3 0
3 years ago
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