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Zielflug [23.3K]
3 years ago
14

-6x + 3x = -21 linear equations

Mathematics
2 answers:
snow_tiger [21]3 years ago
8 0

well combine like terms

-3x = -21

divide both sides by -3

x = 7

kompoz [17]3 years ago
5 0

Answer:

x = 7

Step-by-step explanation:

-6x + 3x = -21

Combine like terms

-3x = -21

Divide by -3

-3x/-3 = -21/-3

x = 7

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2 x 10 to the power of 4
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3 years ago
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Find the radius of convergence R, then determine the interval of convergence
Hunter-Best [27]

The radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty}  | \frac{a_{n+1} }{a_{n} } | = β

  • If β < 1, then the series converges
  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here aₙ = (n²/n!) xⁿ⁺³  and  aₙ₊₁ = ((n+1)²/(n+1)!) xⁿ⁺¹⁺³ = ((n+1)²/(n+1)!) xⁿ⁺⁴

Now limit is taken,

\lim_{n \to \infty}  | \frac{a_{n+1} }{a_{n} } | = \lim_{n \to \infty}  | \frac{((n+1)^{2} /(n+1)!) x^{n+4}  }{(n^{2} /n!) x^{n+3}  } |

                      = \lim_{n \to \infty}  | \frac{((n+1)^{2} ) n!x^{n+4}  }{(n+1)!(n^{2} ) x^{n+3}  } |

                      = \lim_{n \to \infty}  | \frac{((1+1/n)^{2} ) x  }{(n+1)} |  

                      =   \lim_{n \to \infty}  | \frac{ x  }{(n+1)} |  = 0 < 1

Since the limit is less than 1 the series is converging.

We get that,

interval of convergence = (-∞, ∞)

radius of convergence R = ∞

Hence the radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series.

Learn more about power series here:

brainly.com/question/18763238

#SPJ1

6 0
1 year ago
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suppose the population of a town is growing exponentially. the population was 4,636 in 2008 and grew to 5,508 in 2018. what is t
Sloan [31]
<h2>94.93</h2>

Step-by-step explanation:

   The standard equation used to model a exponential growth is given by f(t)=Ae^{Bt}

   Given two data points, which are both explicitly a function of time, it is easy to solve the two equations,

4636=Ae^{2008B} ,5508=Ae^{2018B}

Dividing the second equation by the first,

\frac{5508}{4636}=\frac{Ae^{2018B} }{Ae^{2008B} }

e^{10B}=\frac{5508}{4636}

10B=ln(\frac{5508}{4636} )=0.17235

B=0.017235

Substituting in first equation, A=4.32645\textrm{x}10^{-12}

Growth model : f(t)=(4.3265\textrm{x}10^{-12} )e^{0.017235t}

Growth rate=ABe^{Bt}=94.93

∴Approximate growth rate as of 2018 = 95

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A rectangular farm (6 miles by 2 miles)
tankabanditka [31]

Answer:

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Step-by-step explanation:

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Need help, please explain the answer
Mkey [24]

Answer:

Step-by-step explanation:

U have to multiply 49 by 49 and then subtract 9

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