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AVprozaik [17]
3 years ago
10

You double the radius of a sphere. How does this affect the volume?

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
The volume of a sphere is defined as:
V=(4*pi*r^3)/3
then, if we double the radius of the sphere (r=2r):
V=(4*pi*(2r)^3)/3
V=(4*pi*(2^3*r^3))/3
V=(4*pi*r^3)/3*8

Then, the answer is that if you double the radius of the sphere, its volume is increased 8 times.
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2/9 of the members are boys in a community service club. if there are 95 more girls than boys, how many girls are there in club?
Talja [164]

Answer:

There are 171 members in the club

Number of boys = 38

Number of girls = 133

Step-by-step explanation:

Let

x = total members of the club

Boys = 2/9x

if there are 95 more girls than boys

Girls = 2/9x + 95

how many girls are there in club?

Total members in the club = boys + girls

x = 2/9x + 2/9x + 95

x = 2+2/9x + 95

x = 4/9x + 95

x - 4/9x = 95

9x-4x/9 = 95

5/9x = 95

Divide both sides by 5/9

x = 95 ÷ 5/9

= 95 × 9/5

= 855/5

= 171

boys = 2/9x

= 2/9 * 171

= 342 / 9

= 38

Girls = 2/9x + 95

= 38 + 95

= 133

Total = 38 + 133

= 171

There are 171 members in the club

Number of boys = 38

Number of girls = 133

5 0
3 years ago
F divided by 28 equal 24
BabaBlast [244]
You can translate to:

F ÷ 28 = 24

F/28 = 24          Cross Multiply

F = 28 * 24

F = 672

6 0
4 years ago
Read 2 more answers
How many solutions does this system have?<br> y = -2x + 4<br> y = x^2 - 2x +4
AVprozaik [17]

Answer:

One Solution

Step-by-step explanation:

6 0
3 years ago
The volume of the box below is 1.5 cubic inches. Which of the following are possible dimensions of the box.
anygoal [31]
I’m not sure what u mean?
7 0
4 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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