At chemical equilibrium, the rates<span> of the forward </span>reaction<span> and reverse </span>reactions<span> are: 18.2. a. equal to 0. c. at a ... </span>Spontaneous reactions<span>: 18.4. a. are </span>always exothermic<span>. b. </span>always take place<span> at a </span>rapid rate<span>. </span>
Answer:
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Explanation:
The molarity of a given solution is defined as the total number of moles of solute per litre of solution.
\(Molarity = \frac{n}{V}\)
Here,
M is the molality of the solution
n is the number of moles of the solute
V is the volume of solution given in terms of litres
Molecular weight of oxalic acid (H2C2O4.2H2O) = 126 g/mol.
M = n/V
0.1 M = n/0.25L
n = 0. 025 mol
Number of moles = Given mass/Molar mass
0. 025 mol = m / 126
m = 3.15 g
So, amount of oxalic acid is 3.15 g
The answer is D
Step by step explaining
Answer:
2KMnO₄ (aq) + 10KBr (aq) + 8H₂SO₄ (aq) -> 2MnSO₄ (aq) + 5Br₂ (aq) + 6K₂SO₄ (aq) + 8H₂O (l)
oxidizing agent = KMnO₄
reducing agent = KBr
Explanation:
KMnO₄ -> <em>2</em><em>M</em><em>n</em><em>⁷</em><em>⁺</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>2</em><em>M</em><em>n</em><em>²</em><em>⁺</em>
KBr -> <em>1</em><em>0</em><em>B</em><em>r</em><em>⁻</em><em>⁺</em><em> </em><em>-</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>B</em><em>r</em><em>⁰</em>