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d1i1m1o1n [39]
4 years ago
11

As photosynthesis occurs in chloroplasts, O2 is produced from _____ via a series of reactions associated with _____. View Availa

ble Hint(s) As photosynthesis occurs in chloroplasts, O2 is produced from _____ via a series of reactions associated with _____. H2O … photosystem I CO2 … Calvin cycle CO2 … photosystem II H2O … photosystem II
Chemistry
1 answer:
Monica [59]4 years ago
6 0

Answer:

H₂O, Photosystem II

Explanation:

  • Photosynthesis is the process that enables autotrophs such as green plants and algae to generate food using water, carbon dioxide and energy from the sun.
  • It occurs in two phases, that is, the light-dependent phase and the light-independent phase.
  • During photosystem II energy from the sun is used to break-down water molecules to yield oxygen and hydrogen ions. Oxygen is released away to the atmosphere while hydrogen ions are used in the next phase to generate ATP molecules.

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Spontaneous reaction are always exothermic always take place at rapid rate
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3 years ago
What mass of oxalic acid is required to prepare 250 mL of a 2.00 M solution?
melamori03 [73]

Answer:

Hope this helps!

Explanation:

The molarity of a given solution is defined as the total number of moles of solute per litre of solution.

\(Molarity = \frac{n}{V}\)

Here,

M is the molality of the solution

n is the number of moles of the solute

V is the volume of solution given in terms of litres

Molecular weight of oxalic acid (H2C2O4.2H2O) = 126 g/mol.

M = n/V

0.1 M = n/0.25L

n = 0. 025 mol

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So, amount of oxalic acid is 3.15 g

6 0
3 years ago
Which part of this chemical process requires energy?
kykrilka [37]
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8 0
3 years ago
Read 2 more answers
Balance the redox reaction by oxidation number or ion electron method and indicate oxidizing and reducing agent . KMno4 + KBr +
Georgia [21]

Answer:

2KMnO₄ (aq) + 10KBr (aq) + 8H₂SO₄ (aq) -> 2MnSO₄ (aq) + 5Br₂ (aq) + 6K₂SO₄ (aq) + 8H₂O (l)

oxidizing agent = KMnO₄

reducing agent = KBr

Explanation:

KMnO₄ -> <em>2</em><em>M</em><em>n</em><em>⁷</em><em>⁺</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>2</em><em>M</em><em>n</em><em>²</em><em>⁺</em>

KBr -> <em>1</em><em>0</em><em>B</em><em>r</em><em>⁻</em><em>⁺</em><em> </em><em>-</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>B</em><em>r</em><em>⁰</em>

6 0
3 years ago
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