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bonufazy [111]
3 years ago
8

Balance the redox reaction by oxidation number or ion electron method and indicate oxidizing and reducing agent . KMno4 + KBr +

H2SO4 approach K2SO4 + MnSO4 + H2O + Br2​
Chemistry
1 answer:
Georgia [21]3 years ago
6 0

Answer:

2KMnO₄ (aq) + 10KBr (aq) + 8H₂SO₄ (aq) -> 2MnSO₄ (aq) + 5Br₂ (aq) + 6K₂SO₄ (aq) + 8H₂O (l)

oxidizing agent = KMnO₄

reducing agent = KBr

Explanation:

KMnO₄ -> <em>2</em><em>M</em><em>n</em><em>⁷</em><em>⁺</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>2</em><em>M</em><em>n</em><em>²</em><em>⁺</em>

KBr -> <em>1</em><em>0</em><em>B</em><em>r</em><em>⁻</em><em>⁺</em><em> </em><em>-</em><em> </em><em>1</em><em>0</em><em>e</em><em>⁻</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>B</em><em>r</em><em>⁰</em>

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