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bija089 [108]
3 years ago
6

A plate of the steel hull of a ship develops a large crack when the ship strikes a reef. Analysis of the steel’s composition sho

ws higher-than-normal levels of an element that could explain why the plate cracked instead of bending. Which element is most likely suspected? iron sulfur chromium nickel '
Chemistry
2 answers:
motikmotik3 years ago
8 0
Probably Sulfur, low mp and hardness compared to the other metals
amid [387]3 years ago
5 0

sulfur ----- is the answer

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Instrument used to measure atmospheric pressure
lisov135 [29]

Answer: barometer

Explanation:

7 0
3 years ago
A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
4 years ago
How many molecules in each sample?<br><br> 64.7 g N2<br> 83 g CCl4<br> 19 g C6H12O6
lilavasa [31]

Answer:

  • 1.39x10²⁴ molecules N₂
  • .25x10²³ molecules CCl₄
  • 6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:

  • 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
  • 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
  • 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:

  • 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
  • 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
  • 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
3 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
Read 2 more answers
For the reaction represented by the equation 
2Fe + O2 → 2FeO, how many moles of iron oxide will be produced from 8.00 mol of ir
STatiana [176]

Answer:

8.00 moles.

Explanation:

The ratio of Fe to FeO  is 2:2 = 1:1,  so 8 moles are produced.

8 0
3 years ago
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