Answer:
1.85 × 10⁸ L
Explanation:
Coal power plants burn large amounts of coal, C(s), in an O₂(g) atmosphere to generate electricity. The chemical reaction responsible for producing this energy is shown below:
C(s) + O₂(g) → CO₂(g)
Determine the volume of CO₂ in liters produced when 100 metric ton of C(s) is completely burned in an O₂ atmosphere. The density of CO₂ is 1.98 kg/m³ (1 metric ton = 1000 kg: 1 m³ = 1000 L)
We can establish the following relations:
- 1 metric ton = 1000 kg
- 1 kg = 1000 g
- The molar mass of C(s) is 12.01 g/mol
- The molar ratio of C(s) to CO₂(g) is 1:1
- The molar mass of CO₂(g) is 44.01 g/mol
- 1.98 kg of CO₂(g) occupy a volume of 1 m³ (density = 1.98 kg/m³)
- 1 m³ = 1000 L
The volume of CO₂ produced when 100 metric ton of C(s) react is:
When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.
Answer:
Explanation:
All the stars we see in the night sky are in our own Milky Way Galaxy. Our galaxy is called the Milky Way because it appears as a milky band of light in the sky when you see it in a really dark area.
Hello!
For this problem, we will be applying <em>Charles' Law</em>:
V1/T1 = V2/T2
Now that we have the formula, let's convert the temperature to Kelvin.
27 + 273 = 300K
Let's plug everything in now!
10/300 = 12.0/x
Simplified:
1/30 = 12.0/x
Cross-multiply:
1x = 30*12.0
<u>x = 360</u>
<em>Check!</em>
10/300 = 12/360
300*12 = 360*10
3600 = 3600
Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.
