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Amiraneli [1.4K]
3 years ago
15

Carbon dioxide is a covalently bonded compound. Based on this type of chemical bond, what is one predictable property of carbon

dioxide gas?
a low solubillity
b low melting point
c high conductivity
d high boiling point
Chemistry
1 answer:
Viktor [21]3 years ago
7 0
B: Low Melting Point. if you need me to send you my notes tomorrow
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The following graph shows a decay chain. Which part of the decay will take the most time? the decay of U-238 to Th-234, the deca
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A- the decay of U-238 to Th-234

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A lab scientist cools a liquid sample of water (2.6 kg) at 0.00°C to -192°C. The water turns to ice as this temperature change o
soldier1979 [14.2K]

<u>Answer:</u> The heat released for the given process is -1892 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(l)(0^oC,273K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(s)(-192^oC,81K)

Pressure is taken as constant.

To calculate the amount of heat released at same temperature, we use the equation:

q=m\times L_{f,v}       ......(1)

where,

q = amount of heat released = ?

m = mass of water/ice

L_{f,v} = latent heat of fusion or vaporization

To calculate the amount of heat released at different temperature, we use the equation:

q=m\times C_{p,m}\times (T_{2}-T_{1})        .......(1)

where,

q = amount of heat released = ?

C_{p,m} = specific heat capacity of medium

m = mass of water/ice

T_2 = final temperature

T_1 = initial temperature

Calculating the heat absorbed for each process:

  • <u>For process 1:</u>

Converting the latent heat of fusion in J/kg, we use the conversion factor:

1 kJ = 1000 J

So, (\frac{-334kJ}{1kg})\times (\frac{1000J}{1kJ})=-334\times 10^3J/kg

We are given:

m=2.6kg\\L_f=-334\times 10^3J/kg

Putting values in equation 1, we get:

q_1=2.6kg\times (-334\times 10^3J/kg)=-868400J

  • <u>For process 2:</u>

We are given:

m=2.6kg\\C_{p,s}=2050J/kg.K\\T_1=273K\T_2=81K

Putting values in equation 2, we get:

q_2=2.6kg\times 2050J/kg.K\times (81-(273))^oC\\\\q_2=1023360J

Total heat absorbed = q_1+q_2

Total heat absorbed = [-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ

Hence, the heat released for the given process is -1892 kJ

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