Answer:
328 ml
Explanation:
We have given final volume =575.2 ml=0.575 L
Final concentration = 0.8012 M
We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles
We have to find initial volume
So initial volume 
Answer:
CH2O
Explanation:
Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.
C = 5.692/14.229 * 100 = 40%
O = 7.582/14.229 * 100 = 53.29%
H = 0.955/14.229 * 100 = 6.71%
We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.
C = 40/12 = 3.333
O = 53.29/16 = 3.33
H = 6.71/2 = 6.71
Dividing by the smaller value which is 3.33
C = 3.33/3.33 = 1
O = 3.33/3.33= 1
H = 6.71/3.33 = 2
The empirical formula of the compound ribose is CH2O
Answer:
CH3COOH
Explanation:
CH3COOH has the highest boiling point because it participates in the strongest intermolecular interactions. The -OH group can participate in hydrogen bonding with other -OH groups. Hydrogen bonds are very strong because they are the result of large partial positive charge on the hydrogen and large partial negative charge on the oxygen. When surrounded by other -OH groups, the partial positive charge on the hydrogen can form temporary bonds with the partial negative charge of an oxygen on another molecule. The stronger the intermolecular interactions, the more difficult they are to overcome, thus increasing the boiling point.
The strongest IMF the other molecules participate in are dipole-dipole. These interactions are not as strong as hydrogen bonding.
Answer:
Car B has a greater momentum than car A
Explanation:
Given data:
Mass of car A = 1200 Kg
speed of car A = 22 km/hr
Mass of car B = 1200 Kg
speed of car B = 25 Km/hr
Solution:
For car A:
p = mv
p = 1200 Kg × 22 km/hr
p = 26400 kg.km/hr
For car B:
p = mv
p = 1200 Kg × 25 km/hr
p = 30,000 kg.km/hr
