Answer:
<u>6</u><u>,</u>15,265=lakh
6,15,2<u>6</u>5=tens
hope it helps.
I need help finding the value of x so that all triangles have the same perimeter
1 answer:
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Answer: A. x= 5"
Step-by-step explanation:
ORIGINAL/NEW = 11"/7" = 8.5"/x
x = 7" x 8.5"/11" = 59.5"/11 = 5.409 ≅ 5.41"
If we wanted to keep most of the engraving, we would adjust the larger dimension, but we have been asked to adjust one dimension to 5", since it is said that C. x = 5.41 is incorrect
Then we will adjust the minor dimension to 5"
ORIGINAL/NEW = 11"/y = 8.5"/5"
y= 11" x 5"/8.5" = 6.47"
Then the new dimensions of the paper are 6.47" x 5" to fit an 7" x 5" frame
Answer: A. x= 5"
e.
5^0 = 1; 5^1 = 5; 5^2 = 25; 5^(-1) = 1/5; 5^(-2) = 1/25
This is an exponential function since the exponent is a variable.
Function: f(x) = 5^x
Recursive:
f.
Look at f(x) = x^2 for x = -2, -1, 0, 1, 2
f(-2) = 4
f(-1) = 1
f(0) = 0
f(1) = 1
f(2) = 2
Now look at the y-values in the table. They are the same we have here added to 5.
Your function is a quadratic function.
f(x) = x^2 + 5