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2 years ago

C=1/4 (d+3) make d the subject

Mathematics

1 answer:

trasher [3.6K]2 years ago

4 0

Answer:

4c-3=d

Step-by-step explanation:

4c=d+3

4c-3=d

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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

Question 6

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

Question 7

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

Question 8

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

1 year ago

Use properties to evaluate (-25) HIS O A. – 15 5 O B. 5 C. - OC. 15 O D. 1

Arisa [49]

Answer:

-15/4

Step-by-step explanation:

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1 year ago

Read 2 more answers

Margaret manages a second-hand clothing store. The store advertises that is you buy 3 items, you will get 15% off the most expen

denis23 [38]

The answer to this question would be $49.33

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3 years ago

ASAP PLS ANSWER! TY! Fifteen members of the math club each wore a T-shirt with a number printed on the front. The students’ name

tigry1 [53]

Answer:

The whole numbers

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2 years ago

Bob order 151/2 pound of cherrys fron the farm,this year they want to order 1 1/4 more pound but then 2/5 of the order they want

noname [10]

Answer:

Percentage of cherries = 60 %

Percentage of berries = 40 %

Step-by-step explanation:

He orders 15 1/2 pounds every year.

He wants more= 1 1/4 pounds

So the total pounds = 15 1/2 + 1 1/4

= 15 + 1 + 1/2 + 1/4

= 16 + (2+1)/4

= 16 + 3/4

= 16 3/4 pounds

Out of 16 3/4 pounds they want 2/5 part to be of blue berries.

So blue berries = 16 3/4 * ( 2/5)

= 67/4 * ( 2/5)

= 67/10 = 6 7/10 pounds

Amount of cherries= 16 3/4- 6 7/10

= 10 3/4- 7/10

= 10 (15- 14)/20

= 10 1/20 pounds

Percentage of cherries = Amount of cherries/ Total amount * 100

= 201/20 / 67/4 *100

= 201/20 * 4/67 *100

= 201/335 *100

= 60 %

Percentage of berries = 100- 60 = 40 %

3 0

2 years ago

C=1/4 (d+3) make d the subject​

C=1/4 (d+3) make d the subject