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ivanzaharov [21]
3 years ago
10

Factor completely B. (x+5)²-2(x+5)-24 C. (x+2)²-8(x+2)+15 D. 2(2x-1)²-9(2x-1)+4

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
Ok I don’t use this to answer math questions
But you could use
Photomath in the AppStore
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Working together, Candice and Ximena painted a fence in 8 hours. Last year, Ximena painted the fence by herself. The year before
makkiz [27]

Answer: Time taken by Ximena to paint the fence alone  = 24 hours

Time taken by Candice to paint the fence alone = 12 hours

Step-by-step explanation:

Let x= Time taken by Ximena to paint the fence alone .

Time taken by Candice to paint the fence alone = x-12

As per given , we have

\dfrac{1}{x}+\dfrac{1}{x-12}=\dfrac{1}{8}\\\\\Rightarrow\ \dfrac{x-12+x}{x(x-12)}=\dfrac{1}{8}\\\\\Rightarrow\ 8(2x-12)=x^2-12x\\\\\Rightarrow\ 16x-96=x^2-12x\\\\\Rightarrow\ x^2-12x-16x+96=0\\\\\Rightarrow\ x^2-28x+96=0\\\\\Rightarrow\ x^2-4x-24x+96=0\\\\\Rightarrow\ x(x-4)-24(x-4)=0\\\\\Rightarrow\ (x-4)(x-24)=0\\\\\Rightarrow x=4, 24

if x= 4

Time taken by Ximena = 4 hours

Time taken by Candice = 4-12 hours =-8 hours which is not possible. (time cannot be negative)

Therefore, x= 24

Such that

Time taken by Ximena to paint the fence alone  = 24 hours

Time taken by Candice to paint the fence alone = 24-12=12 hours

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3 years ago
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andreev551 [17]

Answer:

{10}^{ - 14}

Step-by-step explanation:

\huge\frac{ {10}^{ - 9} }{ {10}^{5} }  \\  \\  \huge =  {10}^{ - 9}  \times  {10}^{ - 5}  \\  \\  \huge =  {10}^{ - 9  + ( - 5)}  \\  \\ \huge =  {10}^{ - 9 - 5}  \\  \\  \huge \orange {=  {10}^{ - 14}}

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In this question, the above given-choice is correct because the account on the same bank has certainly, but when a retirement fund in a company is concerned, you could only have a savings account on their behalf, and the mutual funds must then be distributed, and these several savings accounts can be opened is by tracking the amount they need to save for every savings target.

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5(3 - x) < -2x + 6 please solve for me <3
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What grade are you learning this in
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