Can u help me with this problem thx
1 answer:
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The 95% confidence interval for the population standard deviation will be,
simplifying the equation, we get
The 95% confidence interval exists (9.887, 21.288).
<h3>What is the 95% of confidence interval?</h3>
A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.
So,
where n exists the sample size, exists the sample size
s exists the sample standard deviation.
The degrees of freedom will be n - 1 i.e.15 - 1 = 14.
For a 95% confidence interval, the level of significance will be .
The 95% confidence interval for the population standard deviation will be,
substitute the values in the above equation, we get
simplifying the above equation, we get
The 95% confidence interval exists (9.887, 21.288).
To learn more about confidence interval refer to:
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Answer: 7.2 $ will be needed to get 6 Euros.
Step-by-step explanation:
Given : 3$ could be exchanged for 2.5 euros
That means :
To get 2.5 euros , dollars needed are = 3$
By using Unitary method:
To get 1 euro , dollars needed are = $
To get 6 euros , dollars needed are = $
Thus 7.2 $ will be needed to get 6 Euros.