step 2: Chris added the exponents when he should have multiplied them
162 = never use a credit card
1223 = use credit card sometimes
2831 = use a credit card frequently
Probability that a randomly selected person uses a credit card frequently:
1223 / 162 + 1223 + 2831
1223 / 4216
As a percentage, this is about a 29 percent chance. I guess you could say it's unlikely, because the probability is only 29 percent.
The fact that the survey was taken on the internet means it's not really a reliable survey, because only those who have access to the internet would be able to take the survey, which rules out a good group of people.
Step-by-step explanation:
Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])
Given
first term a1 = -2
second term a2 = 2
We are to get the first 8 terms. Given the sequence
a[n]=a[n-2](3-a[n-1])
a[3]=a[3-2](3-a[3-1])
a[3]=a[1](3-a[2])
a[3]=-2(3-2)
a3 = -2
a[n]=a[n-2](3-a[n-1])
a[4]=a[4-2](3-a[4-1])
a[4]=a[2](3-a[3])
a[4]=2(3+2)
a4= 10
a[5]=a[n-2](3-a[n-1])
a[5]=a[5-2](3-a[5-1])
a[5]=a[3](3-a[4])
a[5]=-3(3-10)
a5 = -3(-7)
a5 = 21
a[6]=a[n-2](3-a[n-1])
a[6]=a[6-2](3-a[6-1])
a[6]=a[4](3-a[5])
a[6]= 10(3-21)
a6 = 10(-18)
a6 = -180
a[n]=a[n-2](3-a[n-1])
a[7]=a[7-2](3-a[7-1])
a[7]=a[5](3-a[6])
a[7]= 21(3+180)
a7 = 21(183)
a7 = 3,843
a[8]=a[n-2](3-a[n-1])
a[8]=a[8-2](3-a[8-1])
a[8]=a[6](3-a[7])
a[8]=-180(3-3843)
a8 = -180(-3840)
a8 = 691,200
Answer:
, 
, and 
Step-by-step explanation:
<-- Given
<-- Factor out m²
<-- Factor out n³
<-- Factor out 8
<-- Difference of Squares
Therefore, the factors are , , and
Answer:because it wants to know the answer cause maybe it’s a little elephant child
Step-by-step explanation:
