at the ring toss booth in a carnival 8 people lost and forty people won. how many times as many people won as lost?

What are the slope and the y-intercept of the linear function that is represented by the equation y=-10x+1

RUDIKE [14]

<h3>Answer:</h3>

The slope is $-10$ and the y-intercept is $1$ .

<h3>Explanation:</h3>

This function is written in slope-intercept form, which is $y=mx+b$ . In this form, $m$ is the slope and $b$ is the y-intercept.

In this case, $m=-10$ and $b=1$ , so those are the answers to this problem.

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3 years ago

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The polynomial -x^3-x^2+12x represents the volume of a rectangular aqautic tank in cubic feet. the length of the tank is (x+4).

Verizon [17]

Answer:

<h2>a. It should look for 3 linear factors.</h2><h2>b. There are 3 dimensions.</h2><h2>c. x = 1.7</h2><h2>d. Maximum value is 12.597</h2>

Step-by-step explanation:

a.

$-x^{3} - x^{2} + 12 \timesx$ = $-x^{3} - 4 \timesx^{2} + 3 \timesx^{2} +12 \timesx$ = $-(x + 4) \timesx^{2} + 3 \timesx \times(x + 4)$ = $(x + 4) \timesx \times (x + 3)$

Hence the factorized form of the volume of the poly is $(x + 4) \timesx \times (x + 3)$

3 linear factors should needed to be look for.

b.

The 3 dimensions are (x + 4), x, (x + 3).

c.

Let, f(x) = $-x^{3} - x^{2} + 12 \timesx$

Now, $\frac{d f(x)}{dx}$ = $-3 \timesx^{2} -2 \timesx + 12$

Let $f1(x)$ = $-3 \timesx^{2} -2 \timesx + 12$ and $f2(x)$ = $\frac{d f1(x)}{dx}$ = $-3 \timesx -2$

The value will be maximum, if f1(x) = 0 and f2(x) < 0.

$f1(x) = 0$ \\ $3 \timesx^{2} + 2 \timesx -12 = 0$ \\ $x = \frac{- 2 + \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3} , \frac{- 2 - \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3}$