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Furkat [3]
3 years ago
13

A 2-column table with 8 rows. The first column is labeled x with entries negative 6, negative 5, negative 4, negative 3, negativ

e 2, negative 1, 0, 1. The second column is labeled f of x with entries 34, 3, negative 10, negative 11, negative 6, negative 1, negative 2, negative 15. Using only the values given in the table for the function, f(x), what is the interval of x-values over which the function is increasing? (–6, –3) (–3, –1) (–3, 0) (–6, –5)
Mathematics
3 answers:
ale4655 [162]3 years ago
5 0

Answer:

A 2-column table with 8 rows. The first column is labeled x with entries negative 6, negative 5, negative 4, negative 3, negative 2, negative 1, 0, 1. The second column is labeled f of x with entries 34, 3, negative 10, negative 11, negative 6, negative 1, negative 2, negative 15.

Using only the values given in the table for the function, f(x), what is the interval of x-values over which the function is increasing?

(–3, –1)

fenix001 [56]3 years ago
4 0

Answer:

Step-by-step explanation:

The only place that the function is increasing is [-3, -1] (learn your interval notation). At x = -3, y = -11; at x = -2, y = -6 (-6 is greater than -11); and at x = -1, y = -1 (-1 is greater than -6). The next x value, 0, returns a y value of -2. But -2 is less than -1, the value before it, so it begins deceasing again at x = 0.

Naetoosmart2 years ago
0 0

B (-3,-1) is the answer

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The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
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The length of the rectangle = 16 meters

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<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

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                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

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b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

The product of -26\times21 = -546

The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

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